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  • lambda表达式

    lambda表达式有个限制,那就是只能引用 final 或 final 局部变量,这就是说不能在lambda内部修改定义在域外的变量。

    Compile time error : local variables referenced from a lambda expression must be final or effectively final

    1,List转Map//针对重复key的 覆盖之前的value  

    List<Person> list = new ArrayList<>();
    Map<String, Person> map2 = list.stream().filter(e->StringUtil.isNotBlank(e.getName())).collect(Collectors.toMap(Person::getName , (p) -> p,(k,v)->v));
    
    //value为空,直接存放  不调用map.merge
    Map<String, String> map3 = list.stream().collect(Collector.of(HashMap::new, (m,per)->m.put(per.getName(),per.getSex()), (k,v)->v, Characteristics.IDENTITY_FINISH));

      

    Map<Integer, List<Apple>> groupBy = appleList.stream().collect(Collectors.groupingBy(Apple::getId));

    2,List转List

    List<String> userIdList = Lists.newArrayList();
    List<SubUserVO> subUserVOList = new ArrayList<>();
    subUserVOList.forEach(e -> userIdList.add(e.getId()));
    List<CluePoolDO> search = new ArrayList<>();
    List<Long> clueIds = search.stream().map(CluePoolDO::getId).collect(Collectors.toList());

    3,条件过滤

    List<String> strList = new ArrayList<>();
    List<String> filtered = strList.stream().filter(x -> x.length()> 2).collect(Collectors.toList());
    
    ArrayList<String> httpStrsTmp=new ArrayList<>();
    if(httpStrsTmp.stream().filter(f->f.equals("x")).count()<=0){
    	//xxxxxx
    }
    

      

    4,List转拼接字符串

    List<String> G7 = Arrays.asList("USA", "Japan", "France", "Germany", "Italy", "U.K.","Canada");
    String G7Countries = G7.stream().map(x -> x.toUpperCase()).collect(Collectors.joining(", "));
    

    5,List的最大,小,求和,平均值计算

    List<Integer> primes = Arrays.asList(2, 3, 5, 7, 11, 13, 17, 19, 23, 29);
    IntSummaryStatistics stats = primes.stream().mapToInt((x) -> x).summaryStatistics();
    System.out.println("最大值 : " + stats.getMax());
    System.out.println("最小值 : " + stats.getMin());
    System.out.println("总   和 : " + stats.getSum());
    System.out.println("平均值 : " + stats.getAverage());
    

    6,List迭代

    List<OrderItem> itemList = new ArrayList<>();
    itemList.stream().forEach(item -> {
        System.out.println(item.getId());
    });
    List features = Arrays.asList("Lambdas", "Default Method", "Stream API", "Date and Time API");
    features.forEach(n -> System.out.println(n));
    或者
    features.forEach(System.out::println);
    

    7,List去重

    List<String> originList = new ArrayList<>();
    originList  = originList.stream().distinct().collect(Collectors.toList());
    

      

    // 将评论时间按照倒序排列后再放入
    List<FbCommentVO> comments = fbPosts.getComments();
    if (!CollectionUtils.isEmpty(comments)) {
        comments.sort(Comparator.comparing(FbCommentVO::getCommentTime).reversed());
    }

     8,排序(reversed反转)

    List<Human> humans = Lists.newArrayList(new Human("Sarah", 12), new Human("Sarah", 10), new Human("Zack", 12));
    humans.sort(Comparator.comparing(Human::getName).thenComparing(Human::getAge).reversed());


    List<ShopSellerMenuVO> collect = list.stream().sorted(Comparator.comparing(ShopSellerMenuVO::getId)).collect(Collectors.toList());
     

     9,获取list最大、最小的一条

    List<Date> list = new ArrayList();
    Date maxDate = list.stream().max((o1,o2) -> o1.compareTo(o2)).get();
    Date minDate = list.stream().min((o1,o2) -> o1.compareTo(o2)).get();
    
    List<Employee> userList = new ArrayList();
    Employee max = userList.stream().max(Comparator.comparingInt(Employee ::getAge)).get();
    Employee min= userList.stream().min(Comparator.comparingInt(Employee ::getAge)).get();
    //注意空指针,对年龄判空
    

      

    10,移动集合中元素的位置

    Collections.swap(list,fromIndex,toIndex);

      

    11,分组

    productSpecNumsList.stream().collect(groupingBy(ProductSpecNums::getSpecId));

      

      

      

      

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  • 原文地址:https://www.cnblogs.com/wanhua-wu/p/9035980.html
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