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  • 【模板】Tarjan缩点+建新图+dfs树上dp

    然后是才发现洛谷的模板题之前一直没过,看了一下才发现是建新图时把方向建返了....这猪脑子。

    于是重新学了一遍Tarjan的思路,果然靠背板子的话真就一点都回忆不起来啊。

    又pass一个点叻!yep!

    P3387 【模板】缩点

    #include<bits/stdc++.h>
    
    const int N = 100005;
    
    using namespace std;
    
    struct Node {
        int nex, v;
        Node(int nex = 0, int v = 0) :
            nex(nex), v(v) { }
    } Edge[N];
    
    struct node {
        int nex, v;
        node(int nex = 0, int v = 0) :
            nex(nex), v(v) { }
    } Edgeco[N];
    
    int stot, h[10005];
    void add(int u, int v) {
        Edge[++stot] = Node(h[u], v);
        h[u] = stot;
    }
    
    int stotco, hco[10005];
    void addco(int u, int v) {
        Edgeco[++stotco] = node(hco[u], v);
        hco[u] = stotco;
    }
    
    int dfn[10005], low[10005], idc, color[10005], tp, stk[50005], cnt, sum[10005], val[10005];
    void Tarjan(int u) {
        dfn[u] = low[u] = ++ idc;
        stk[++tp] = u;
        for(int i = h[u]; i; i = Edge[i].nex) {
            int v = Edge[i].v;
            if(!dfn[v])    {
                Tarjan(v);    low[u] = min(low[v], low[u]);
            } else if(!color[v])    low[u] = min(dfn[v], low[u]);
        }
        if(dfn[u] == low[u]) {
            cnt ++; int x;
            do {
                x = stk[tp--];
                color[x] = cnt;
                sum[cnt] += val[x];
            } while(x != u);
        }
    }
    
    int n, m;
    int f[10005];
    void dfs(int u) {
        if(f[u])    return ;
        f[u] = sum[u];
        for(int i = hco[u]; i; i = Edgeco[i].nex) {
            int v = Edgeco[i].v;
            dfs(v);
            f[u] = max(f[u], sum[u] + f[v]);
        }
    }
    
    int main() {
        scanf("%d%d", &n, &m);
        for(int i = 1; i <= n; i ++)
            scanf("%d", &val[i]);
        for(int i = 1; i <= m; i ++) {
            int u, v;
            scanf("%d%d", &u, &v);
            add(u, v);
        }
        for(int i = 1; i <= n; i ++)
            if(!color[i])
                Tarjan(i);
        for(int i = 1; i <= n; i ++)
            for(int j = h[i]; j; j = Edge[j].nex) {
                int v = Edge[j].v;
                if (color[v] != color[i]) addco(color[i], color[v]);
            }
        int ans = 0;
        for(int i = 1; i <= cnt; i ++)
            if(!f[i]) {
                dfs(i);    ans = max(ans, f[i]);
            }
        printf("%d", ans);
        return 0;
    }

    然后最近看了一下之前校队选拔的题,好!难!怎么那么多DP数论,突然慌慌。但是巨巨学长说只要能做出来最简单的几道就能苟进队了,我!信!个!鬼!于是去水模板题了。

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  • 原文地址:https://www.cnblogs.com/wans-caesar-02111007/p/13939007.html
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