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  • poj2777

    poj2777
    区间修改,区间查询
    mark=-1表示这个区间有多种颜色,否则就1种

    #include<iostream>
    #include<cstdio>
    #include<queue>
    #include<algorithm>
    #include<cmath>
    #include<ctime>
    #include<set>
    #include<map>
    #include<stack>
    #include<cstring>
    #define inf 2147483647
    #define For(i,a,b) for(register long long i=a;i<=b;i++)
    #define p(a) putchar(a)
    #define g() getchar()
    #define N 100010
    using namespace std;
    long long a[N],n,m,k,x,y,t,cnt;
    bool vis[50];
    char flag;
    struct seg{
        long long mark;
    }s[N<<3];
    
    void in(long long &x){
        long long y=1;char c=getchar();x=0;
        while(c<'0'||c>'9'){if(c=='-')y=-1;c=getchar();}
        while(c<='9'&&c>='0'){ x=(x<<1)+(x<<3)+c-'0';c=getchar();}
        x*=y;
    }
    void o(long long x){
        if(x<0){p('-');x=-x;}
        if(x>9)o(x/10);
        p(x%10+'0');
    }
    
    inline void build(long long rt,long long l,long long r){
        s[rt].mark=1;
        if(l==r) return;
        long long mid=(l+r)>>1;
        build(rt<<1, l, mid);
        build(rt<<1|1, mid+1, r);
    }
    
    inline void pushdown(long long rt,long long l,long long r){
        if(s[rt].mark!=-1){
            s[rt<<1].mark=s[rt<<1|1].mark=s[rt].mark;
            s[rt].mark=-1;
        }
    }
    
    inline void update(long long rt,long long nl,long long nr,long long l,long long r,long long k){
        if(nr<l||nl>r)return;
        if(nl>=l&&nr<=r){
            s[rt].mark=k;
            return;
        }
        pushdown(rt,nl,nr);
        long long mid=(nl+nr)>>1;
        update(rt<<1, nl, mid, l, r, k);
        update(rt<<1|1, mid+1, nr, l, r, k);
    }
    
    inline void query(long long rt,long long nl,long long nr,long long l,long long r){
        if(nl>r||nr<l) return;
        if(s[rt].mark!=-1){
            vis[s[rt].mark]=1;
            return;
        }    
        long long mid=(nl+nr)>>1;
        query(rt<<1, nl, mid, l, r);
        query(rt<<1|1, mid+1, nr, l, r);
    }
    
    int main(){
        in(n);in(t);in(m);
        build(1,1,n);
        For(i,1,m){
            cin>>flag;
            if(flag=='C'){
                in(x);in(y);in(k);
                update(1,1,n,x,y,k);
            }
            else{
                memset(vis,0,sizeof(vis));
                in(x);in(y);
                query(1,1,n,x,y);
                cnt=0;
                For(j,1,t) if(vis[j]) cnt++;
                o(cnt);p('
    ');
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/war1111/p/11560321.html
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