乘法逆元(递推)

#include<iostream>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cmath>
#include<algorithm>
#define ll long long
using namespace std;
ll n,p,a[3000001];
int main()
{
    scanf("%lld%lld",&n,&p);
    a[1]=1;
    printf("%lld
",a[1]);
    for(int i=2;i<=n;i++)
    {
        a[i]=-(p/i)*a[p%i];
        a[i]=(a[i]%p+p)%p;
        printf("%lld
",a[i]);
    }
    return 0;
}