mysql 根据生日计算年龄，并查询在18-25之间的语句

select
    id,
    DATE_FORMAT(birthday,"%Y-%m-%d") birthday,
    CURDATE() ,
    (year(now())-year(birthday)-1) + ( DATE_FORMAT(birthday, '%m%d') <= DATE_FORMAT(NOW(), '%m%d') ) as age
from
    t_user where id in (1,55000,55001);

select (year(curdate())-year(birthday)-1+(DATE_FORMAT(birthday,'%m%d')<=(DATE_FORMAT(curdate(),'%m%d')))) as '年龄' from employee;

(year(curdate())-year(birthday)-1+(DATE_FORMAT(birthday,'%m%d')<=(DATE_FORMAT(curdate(),'%m%d'))))  BETWEEN 18AND 25

select (year(curdate())-year(birthday)-1+(DATE_FORMAT(birthday,'%m%d')<=(DATE_FORMAT(curdate(),'%m%d')))) as '年龄' from employee;

 参考：

http://blog.csdn.net/a673341766/article/details/32321881

http://blog.csdn.net/zm2714/article/details/7896381