js获取url参数

js获取url参数，参数在？后边

方法1：

function QueryString(item)
{
    var sValue=location.search.match(new RegExp("[\?\&]"+item+"=([^\&]*)(\&?)","i"))
    return sValue?sValue[1]:sValue
}

//使用方法
//url=http://www.xxx.com?ID=100&name=dom
var ID=QueryString("ID");  
var name=QueryString("name");

方法2：

function GetRequest() {
            var url = location.search; //获取url中"?"符后的字串
            var theRequest = new Object();
            if (url.indexOf("?") != -1) {
                var str = url.substr(1);
                strs = str.split("&");
                for (var i = 0; i < strs.length; i++) {
                    theRequest[strs[i].split("=")[0]] = decodeURIComponent(strs[i].split("=")[1]);
                }
            }
            return theRequest;
        }
        var RequestRef = GetRequest()["r"];
        console.log(RequestRef)