zoukankan      html  css  js  c++  java
  • HDOJ 1058 Humble Numbers(打表过)

    Problem Description
    A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, … shows the first 20 humble numbers.

    Write a program to find and print the nth element in this sequence

    Input
    The input consists of one or more test cases. Each test case consists of one integer n with 1 <= n <= 5842. Input is terminated by a value of zero (0) for n.

    Output
    For each test case, print one line saying “The nth humble number is number.”. Depending on the value of n, the correct suffix “st”, “nd”, “rd”, or “th” for the ordinal number nth has to be used like it is shown in the sample output.

    Sample Input
    1
    2
    3
    4
    11
    12
    13
    21
    22
    23
    100
    1000
    5842
    0

    Sample Output
    The 1st humble number is 1.
    The 2nd humble number is 2.
    The 3rd humble number is 3.
    The 4th humble number is 4.
    The 11th humble number is 12.
    The 12th humble number is 14.
    The 13th humble number is 15.
    The 21st humble number is 28.
    The 22nd humble number is 30.
    The 23rd humble number is 32.
    The 100th humble number is 450.
    The 1000th humble number is 385875.
    The 5842nd humble number is 2000000000.

    打表做的。
    题意输出的格式挺难懂的。。。
    解释一下格式:
    如果输入的数:
    对10取余,余数等于1且对100取余,余数不为11.则输出的是”st”;
    对10取余,余数等于2且对100取余,余数不为12.则输出的是”nd”;
    对10取余,余数等于3且对100取余,余数不为13.则输出的是”rd”;
    其他的全部为“th”。

    import java.util.Scanner;
    
    public class Main{
        static int db[] = new int[5845];
        public static void main(String[] args) {
            dabiao();
            Scanner sc = new Scanner(System.in);
            while(sc.hasNext()){
                int n  = sc.nextInt();
                if(n==0){
                    return;
                }
                System.out.printf("The %d", n);
                if(n%10 == 1 && n%100 != 11){
                    System.out.printf("st");
                }
                else if(n%10 == 2 && n%100 != 12){
                    System.out.printf("nd");
                }
                else if(n%10 == 3 && n%100 != 13){
                    System.out.printf("rd");
                }
                else System.out.printf("th");
    
                System.out.printf(" humble number is %d.",db[n]);
                System.out.println();
    
            }
        }
        private static void dabiao() {
            db[1]=1;
            int a1=1,a2=1,a3=1,a4=1;
            for(int i=2;i<=5842;i++){
                db[i]=min4(db[a1]*2,db[a2]*3,db[a3]*5,db[a4]*7);
    
                if(db[i]==db[a1]*2){
                    a1++;
                }
                if(db[i]==db[a2]*3){
                    a2++;
                }
                if(db[i]==db[a3]*5){
                    a3++;
                }
                if(db[i]==db[a4]*7){
                    a4++;
                }
                //没有这个防护一样能过
    //          if(db[i]==db[i-1]){
    //              i--;
    //          }
            }
        }
    
        private static int min4(int i, int j, int k, int l) {
            return min(i,min(j,min(k,l)));
        }
        private static int min(int k, int l) {
            if(k<l){
                return k;
            }else{
                return l;
            }
        }
    
    }
    
  • 相关阅读:
    北斗授时服务器,时间同步服务器,网络时钟服务器2020最新报价
    北斗GPS卫星同步时钟让采集系统更精准
    ntp时钟服务器(医院时钟系统)在网络里的作用
    「Excel技巧」Excel中根据某列的值去汇总另外一列的值
    「Excel技巧」Excel技巧之如何看文件里的宏?
    「杂谈」同学聚会最悲哀的事情
    torch 中的损失函数
    CJJ/T 302-2019 城市园林绿化监督管理信息系统工程技术标准
    SJ/T 11362-2006 企业信息化技术规范 制造执行系统(MES)规范
    1. C语言三个数从小到大排序/输出
  • 原文地址:https://www.cnblogs.com/webmen/p/5739339.html
Copyright © 2011-2022 走看看