zoukankan      html  css  js  c++  java
  • 练习题

    1.select Sname,Ssex,Class from student
    2.select distinct depart from teacher
    3.select * from student
    4.select * from score where degree between 60 and 80
    5.select * from score where degree in(85,86,88)
    6.select * from student where class='95031' or Ssex='女'
    7.select * from student order by class desc
    8.select * from score order by cno,degree desc
    9.select count(*) from student where class='95031'
    10. select sno,cno from score where degree =(select max(degree) from score)
    11.select cno,avg(degree) from score group by cno
    12.select avg(degree) from score where cno like'3%' group by cno having count(*)>=5
    select avg(degree) from score group by cno having count(*)>=5 and cno like'3%'

    13.select sno from score where degree>70 and degree<90

    14.select sname,cno,degree from score join student on score.sno = student.sno

    15.select sno,cname,degree from score join course on score.cno=course.cno

    16.select sname,cname,degree from score join student on student.sno=score.sno join course on score.cno = course.cno

    select sname,cname,degree from score,student,course where student.sno=score.sno and score.cno = course.cno

    17.select avg(degree) from score where sno in(select sno from student where class='95033')

    18.select sno,cno,rank from score,grade where degree between low and upp

    19. select * from score where cno='3-105' and degree>(select degree from score where sno='109' and cno='3-105')

    select * from score where cno='3-105' and degree>(select max(degree) from score where sno='109')

    20. select * from score a where sno in (select sno from score group by sno having count(*)>1) and degree <(select max(degree) from score b where b.cno=a.cno)

    21.select * from score where degree>(select degree from score where sno='109' and cno='3-105')

    22.select * from student where YEAR(sbirthday) = (select YEAR(sbirthday) from student where sno='108')

    23. select * from score where cno in(select cno from course where tno in(select tno from teacher where tname='张旭'))

    24.select tname from teacher where tno in(select tno from course where cno in(select cno from score group by cno having count(*)>=5))

    25.select * from student where class in('95033','95031')

    26.select distinct cno from score where degree>85

    27.select * from score where cno in(select cno from course where tno in(select tno from teacher where depart='计算机系'))

    28.select tname,prof from teacher where depart='计算机系' and prof not in(select prof from teacher where depart='电子工程系')union
    select tname,prof from teacher where depart='电子工程系' and prof not in(select prof from teacher where depart='计算机系')

    select tname,prof from teacher a where prof not in(select prof from teacher b where b.depart != a.depart)

    29.select * from score where cno='3-105' and degree>any(select degree from score where cno='3-245')

  • 相关阅读:
    python基础5之装饰器
    python基础4之递归、lambda、深浅copy
    python基础3之文件操作、字符编码解码、函数介绍
    python基础1之python介绍、安装、变量和字符编码、数据类型、输入输出、数据运算、循环
    python基础2之字符串、列表、字典、集合
    Mysql主从复制的实现
    LNMP一键安装脚本
    LNMP搭建(CentOS 6.3+Nginx 1.2.0+PHP 5.3.15(fpm)+ MySQL 5.5.35)
    整合apache+tomcat+keepalived实现高可用tomcat集群
    浅谈CSRF
  • 原文地址:https://www.cnblogs.com/weiwenxin01/p/5752243.html
Copyright © 2011-2022 走看看