写一个函数days,实现第1 题的计算。由主函数将年、月、日传递给days函数,计算后将日子数传回主函数输出

写一个函数days,实现第1 题的计算。由主函数将年、月、日传递给days函数,计算后将日子数传回主函数输出。

#include <stdio.h>

struct Date{
	int year;
	int month;
	int day;
};

int Days(struct Date date)
{
	static int Days[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

	int i, days = 0;
	for (i = 1; i < date.month; i++)
		days += Days[i];
	days += date.day;
	//如果包含闰年的二月，天数加1
	if (date.month > 2)
	{
		if (date.year % 400 == 0 || (date.year % 4 == 0 && date.year % 100 != 0)){
			++days;
		}
	}
	return days;
}

int main(){
	struct Date date;
	printf("Please give date: ");
	scanf("%d%d%d", &date.year, &date.month, &date.day);
	int days = Days(date);
	printf("It's day %d in the year.
", days);
	return 0;
}

运行截图：