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  • ACM DP Wooden Sticks

    B - Wooden Sticks
    Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu
    Submit Status

    Description

    There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows: 

    (a) The setup time for the first wooden stick is 1 minute. 
    (b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup. 

    You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2). 


    Input 

    The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1<=n<=5000, that represents the number of wooden sticks in the test case, and the second line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces. 


    Output 

    The output should contain the minimum setup time in minutes, one per line. 


    Sample Input 



    4 9 5 2 2 1 3 5 1 4 

    2 2 1 1 2 2 

    1 3 2 2 3 1


    Output for the Sample Input



    3

     
    贪心就不多说了,直接给代码了
    #include <cstdio>
    #include <iostream>
    #include <cstring>
    #include <algorithm>
    
    using namespace std;
    
    struct Stick
    {
        int l;
        int w;
    }stick[5005];
    
    bool cmp(const Stick a,const Stick b)
    {
        if(a.l == b.l)
            return a.w < b.w;
        return a.l < b.l;
    }
    
    bool vis[5005];
    int n ,t;
    int main()
    {
        while(~scanf("%d",&t))
        {
            while(t--)
            {
                scanf("%d",&n);
                for(int i = 0; i < n; i++)
                {
                    scanf("%d%d",&stick[i].l,&stick[i].w);
                }
                sort(stick,stick + n ,cmp);
    
                memset(vis,0,sizeof(vis));
                int num = 0;
                int l,w;
                int cnt = 0,tt = 0;
    
                while(tt < n)
                {
                    vis[num] = 1;
                    tt++;
                    l = stick[num].l;
                    w = stick[num].w;
                    bool flag = false;
    
                    for(int i = num + 1; i < n;i++)
                    {
                        if(!vis[i]&&stick[i].l >= l && stick[i].w >= w)
                        {
                            w = stick[i].w;
                            l = stick[i].l;
                            vis[i] = 1;
                            tt++;
                        }
                        else if(!vis[i]&&!flag)
                        {
                            flag = true;
                            num = i;
                        }
                    }
                    cnt++;
                }
                printf("%d
    ",cnt);
            }
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/wejex/p/3227414.html
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