zoukankan      html  css  js  c++  java
  • 抄写作业

    //例题9.1//
    #include<stdio.h>
    int main()
    {struct Student
      {long int num;    //定义长整形num// 
      char name[20];    //定义字符数组name,记住:当没有初始化时,字符数组中数不能空// 
      char sex;     
      char addr[20];   
      }a={10101,"Li Lin",'M',"123 Beijing Road"};      //给定义的数都初始化,注意:字符初始化要有单引号,字符串初始化要有双引号//
      printf("NO.:%ld
    name:%s
    sex:%c
    address:%s
    ",a.num,a.name,a.sex,a.addr);   //输出的变量要对应相应的格式符// 
      return 0;
    }
    NO.:10101
    name:Li Lin
    sex:M
    address:123 Beijing Road
    
    --------------------------------
    Process exited after 0.4356 seconds with return value 0
    请按任意键继续. . .
    

      

    //例题9.2//
    #include<stdio.h>
    int main()
    {struct student
    	{  int num;               
    	   char name[20];         
    	   float score;
    	}student1,student2;
    	scanf("%d%s%f",&student1.num,&student1.name,&student1.score);       //输入学生1,2的各项值,再输入中一定得加&// 
    	scanf("%d%s%f",&student2.num,&student2.name,&student2.score);
    	printf("The higher score is:
    ");
    	if(student1.score>student2.score)                                    //用双重if语句来判断学生们的大小比较// 
    	   printf("%d  %s  %6.2f
    ",student1.num,student1.name,student1.score);
    	else if(student1.score<student2.score)   
    	   printf("%d  %s  %6.2f
    ",student2.num,student2.name,student2.score);
    	else
    	{  printf("%d  %s  %6.2f
    ",student1.num,student1.name,student1.score);
    	   printf("%d  %s  %6.2f
    ",student2.num,student2.name,student2.score);
    	   }   
        return 0;
    }
    10101 ww 88.5
    10103 qq 44.1
    The higher score is:
    10101  ww   88.50
    
    --------------------------------
    Process exited after 16.54 seconds with return value 0
    请按任意键继续. . .
    

      

    //例题9.3//
    #include<string.h>
    #include<stdio.h>
    struct person
    {char name[20];
     int count;
    }leader[3]={"Li",0,"Zhang",0,"Sun",0};
    int main()
    {int i,j;
     char leader_name[20];
     for(i=1;i<=10;i++)
        {scanf("%s",leader_name);
           for(j=0;j<3;j++)                                                  //用包含for循环选出投票数// 
             if(strcmp(leader_name,leader[j].name)==0)leader[j].count++;
    	}
        printf("
    Result:
    ");
        for(i=0;i<3;i++)
             printf("%5s:%d
    ",leader[i].name,leader[i].count);
       return 0;      
    } 
    Li
    Zhang
    Li
    Li
    Sun
    Zhang
    Zhang
    Zhang
    Sun
    Li
    
    Result:
       Li:4
    Zhang:4
      Sun:2
    
    --------------------------------
    Process exited after 62.49 seconds with return value 0
    请按任意键继续. . .
    

      

    //例题9.4//
    #include<stdio.h>
    struct Student 
    {  int num;
       char name[20];
       float score;
    };
    int main() 
    {struct Student stu[5]={{10101,"Zhang",78},{10103,"Wang",98.5},{10106,"Li",86}, {10108,"Ling",73.5},{10110,"Sun",100}};  
     struct Student temp;  
     const int n=5;  
     int i,j,k;  
     printf("The order is:
    ");  
     for(i=0;i<n-1;i++)  
         {k=i;   
          for(j=i+1;j<n;j++)
    	     if(stu[j].score>stu[k].score) 
    		 k=j;
    		 temp=stu[k]; 
    		 stu[k]=stu[i];
    	     stu[i]=temp;
    	 }   
    	 for(i=0;i<n;i++)   
    	      printf("%6d %8s %6.2f
    ",stu[i].num,stu[i].name,stu[i].score);
     printf("
    "); 
     return 0; 
    } 
    The order is:
     10110      Sun 100.00
     10103     Wang  98.50
     10106       Li  86.00
     10101    Zhang  78.00
     10108     Ling  73.50
    
    
    --------------------------------
    Process exited after 0.1495 seconds with return value 0
    请按任意键继续. . .
    

      

    //例题9.5//
    #include<stdio.h>
    #include<string.h> 
    int main() 
    {struct Student  
        {long num;
    	 char name[20];
    	 char sex; 
    	 float score; 
    	};struct Student stu_1;
    	  struct Student *p; 
    	  p=&stu_1; 
    	  stu_1.num=10101; 
    	  strcpy(stu_1.name,"Li Lin"); 
    	  stu_1.sex='M';  
    	  stu_1.score=89.5;  
    	  printf("No.:%ld
    name:%s
    sex:%c
    score:%5.1f
    ",stu_1.num,stu_1.name,stu_1.sex,stu_1.score);  
    	  printf("
    ");  
    	  printf("No.:%ld
    name:%s
    sex:%c
    score:%5.1f
    ",(*p).num,(*p).name,(*p).sex,(*p).score);  
      return 0; 
    } /
    

      

    No.:10101
    name:Li Lin
    sex:M
    score: 89.5
    
    No.:10101
    name:Li Lin
    sex:M
    score: 89.5
    
    --------------------------------
    Process exited after 0.1335 seconds with return value 0
    请按任意键继续. . .  
    //例题9.6//
    #include<stdio.h> 
    struct Student 
    {int num;  
     char name[20]; 
     char sex;
     int age; 
    };struct Student stu[3]={{10101,"Li Lin",'M',18},{10102,"Zhang Fang",'M',19},{10104,"Wang Min",'F',20}}; 
    int main() 
    {struct Student *p;  
     printf("No.    Name                sex age
    "); 
     for(p=stu;p<stu+3;p++) 
     printf("%5d %-20s %2c %4d
    ",p->num,p->name,p->sex,p->age);
     return 0; 
    }
    No.    Name                sex age
    10101 Li Lin                M   18
    10102 Zhang Fang            M   19
    10104 Wang Min              F   20
    
    --------------------------------
    Process exited after 0.1049 seconds with return value 0
    请按任意键继续. . .
    

      

    //例题9.7//
    #include<stdio.h>
    #define N 3 
    struct Student 
    {int num;
     char name[20]; 
     float score[3]; 
     float aver; 
    }; 
    int main() 
    {void input(struct Student stu[]); 
     struct Student max(struct Student stu[]);
     void print(struct Student stud);  
     struct Student stu[N],*p=stu;  
     input(p);  
     print(max(p));  
     return 0; 
    } 
    void input(struct Student stu[])
    {int i;
     printf("请输入各学生的信息:学号、姓名、三门课成绩:
    ");
     for(i=0;i<N;i++) 
         {scanf("%d %s %f %f %f",&stu[i].num,&stu[i].name,&stu[i].score[0],&stu[i].score[1],&stu[i].score[2]);
    	  stu[i].aver=(stu[i].score[0]+stu[i].score[1]+stu[i].score[2])/3.0;
    	 } 
    }  
    struct Student max(struct Student stu[])
    {int i,m=0;
     for(i=0;i<N;i++)
         if(stu[i].aver>stu[m].aver)m=i;
    	 return stu[m]; 
    }
    void print(struct Student stud) 
    {printf("
    成绩最高的学生是:
    ");  
     printf("学号:%d
    姓名:%s
    三门成绩:%5.1f,%5.1f,%5.1f
    平均成绩:%6.2f
    ",stud.num,stud.name,stud.score[0],stud.score[1],stud.score[2],stud.aver);
    }
    
    请输入各学生的信息:学号、姓名、三门课成绩:
    22 ww 44 77 88
    33 qq 44 77 55
    44 ee 66 33 11
    
    成绩最高的学生是:
    学号:22
    姓名:ww
    三门成绩: 44.0, 77.0, 88.0
    平均成绩: 69.67
    
    --------------------------------
    Process exited after 24.56 seconds with return value 0
    请按任意键继续. . .
    

      

    总结:C语言是极易弄错误的一门课,因此需要我们细心查看,要注意标点括号,要查阅出错时程序给的错误提示,并思考出现这种错误的原因,然后逐     层修改。

             

  • 相关阅读:
    C++实现数字媒体三维图像渲染
    C++实现数字媒体三维图像变换
    C++实现数字媒体二维图像变换
    C++实现glut绘制点、直线、多边形、圆
    语音识别之梅尔频谱倒数MFCC(Mel Frequency Cepstrum Coefficient)
    Java中的BigDecimal类精度问题
    spring 手册
    bootstrap 参考文档
    springBoot入门文章
    JNDI
  • 原文地址:https://www.cnblogs.com/wengweng/p/6681872.html
Copyright © 2011-2022 走看看