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  • Linux环境下实现生产者消费者问题

    
    
    #include <stdio.h>
    #include <semaphore.h>
    #include <stdlib.h>
    #include <pthread.h>
    #include <unistd.h>
    
    #define N1 3//定义3个生产者
    #define N2 4//定义4 个消费者
    #define M 10//定义10个大小缓冲区
    
    int in = 0;
    int out = 0;
    
    int buff[M] = {0};//缓冲区大小为10
    
    sem_t empty_sem;//空缓冲区数量
    sem_t full_sem;//满缓冲区数量
    pthread_mutex_t mutex;//互斥访问缓冲区
    
    int product_id = 0;
    int consumer_id = 0;
    
    int data;
    FILE *fp;
    
    void * product()
    {
        int id = ++product_id;
        while(1)
        {
            sleep(1);
            sem_wait(&empty_sem);
            pthread_mutex_lock(&mutex);
            //if(feof(fp) != 0) fseek(fp, 0, SEEK_SET);
            if(fscanf(fp, "%d", &data)==EOF) 
            {
                fseek(fp, 0, SEEK_SET);
                fscanf(fp, "%d", &data);
            }
            in = in % M;
            buff[in] = data;
            printf("Producter %d produce %d in position %d
    ", id, buff[in], in);
            ++in;
            pthread_mutex_unlock(&mutex);
            sem_post(&full_sem);
        }
    }
    
    
    void *consume()
    {
        int id = ++consumer_id;
    
        while(1)
        {
            sleep(1);
            sem_wait(&full_sem);
            pthread_mutex_lock(&mutex);
    
            out = out % M;
            printf("Consumer %d take product  %d in position %d
    ", id, buff[out], out);
            buff[out] = 0;
            ++out;
    
            pthread_mutex_unlock(&mutex);
            sem_post(&empty_sem);
    
        }
    }
    
    
    int main()
    {
        pthread_t id1[N1];//定义生产者线程
        pthread_t id2[N2];//定义消费者线程
    
        int i;
        int ret1[N1];
        int ret2[N2];
    
        int ini1 = sem_init(&empty_sem, 0, M);  //初始化空缓冲区 为 M(10)
        int ini2 = sem_init(&full_sem, 0, 0);//初始化满缓冲区  0
        if(ini1 && ini2 != 0)
        {
            printf("Sem init failed
    ");
            exit(1);
        }
    
        int ini3 = pthread_mutex_init(&mutex, NULL);//初始化互斥信号量
        if(ini3 != 0 )
        {
            printf("mutex init failed
    ");
            exit(1);
        }
        
        fp = fopen("/.data.txt", "r");//打开文件Data.txt
        if(fp == NULL) exit(1);
    
        for(i = 0; i < N1; i++)
        {
            ret1[i] = pthread_create(&id1[i], NULL, product, (void*)(&i));//创建生产者线程
            if(ret1[i] != 0)
            {
                printf("product%d creat failed
    ", i);
                exit(1);
            }
        }
    
        for(i = 0; i< N2; i++)
        {
            ret2[i] = pthread_create(&id2[i], NULL, consume, NULL);//创建消费者线程
            if(ret2[i] != 0)
            {
                printf("consumer%d creat failed
    ", i);
                exit(1);
            }
        }
    
    
        for(i = 0; i < N1; i++) {pthread_join(id1[i], NULL);}
        for(i = 0; i < N2; i++) {pthread_join(id2[i], NULL);}
    
        exit(0);
    
    
    }
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  • 原文地址:https://www.cnblogs.com/wenjieyatou/p/5392764.html
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