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  • 1237. Find Positive Integer Solution for a Given Equation

    Given a function  f(x, y) and a value z, return all positive integer pairs x and y where f(x,y) == z.

    The function is constantly increasing, i.e.:

    • f(x, y) < f(x + 1, y)
    • f(x, y) < f(x, y + 1)

    The function interface is defined like this: 

    interface CustomFunction {
    public:
      // Returns positive integer f(x, y) for any given positive integer x and y.
      int f(int x, int y);
    };
    

    For custom testing purposes you're given an integer function_id and a target z as input, where function_id represent one function from an secret internal list, on the examples you'll know only two functions from the list.  

    You may return the solutions in any order.

    Example 1:

    Input: function_id = 1, z = 5
    Output: [[1,4],[2,3],[3,2],[4,1]]
    Explanation: function_id = 1 means that f(x, y) = x + y

    Example 2:

    Input: function_id = 2, z = 5
    Output: [[1,5],[5,1]]
    Explanation: function_id = 2 means that f(x, y) = x * y
    

    Constraints:

    • 1 <= function_id <= 9
    • 1 <= z <= 100
    • It's guaranteed that the solutions of f(x, y) == z will be on the range 1 <= x, y <= 1000
    • It's also guaranteed that f(x, y) will fit in 32 bit signed integer if 1 <= x, y <= 1000
    class Solution {
        public List<List<Integer>> findSolution(CustomFunction customfunction, int z) {
            List<List<Integer>> res = new ArrayList();
            int x = 1, y = 1000;
            while(x <= 1000 && y > 0){
                int v = customfunction.f(x, y);
                if (v > z) --y;
                else if (v < z) ++x;
                else res.add(Arrays.asList(x++, y--));
            }
            return res;
        }
    }

     https://leetcode.com/problems/find-positive-integer-solution-for-a-given-equation/discuss/414249/JavaC%2B%2BPython-O(X%2BY)

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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/12881437.html
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