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  • 1470. Shuffle the Array

    Given the array nums consisting of 2n elements in the form [x1,x2,...,xn,y1,y2,...,yn].

    Return the array in the form [x1,y1,x2,y2,...,xn,yn].

    Example 1:

    Input: nums = [2,5,1,3,4,7], n = 3
    Output: [2,3,5,4,1,7] 
    Explanation: Since x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 then the answer is [2,3,5,4,1,7].
    

    Example 2:

    Input: nums = [1,2,3,4,4,3,2,1], n = 4
    Output: [1,4,2,3,3,2,4,1]
    

    Example 3:

    Input: nums = [1,1,2,2], n = 2
    Output: [1,2,1,2]
    

    Constraints:

    • 1 <= n <= 500
    • nums.length == 2n
    • 1 <= nums[i] <= 10^3
    class Solution {
        public int[] shuffle(int[] nums, int n) {
            int[] a1 = new int[n];
            int[] a2 = new int[n];
            for(int i = 0; i < 2*n; i++){
                if(i < n){
                    a1[i] = nums[i];
                }
                else a2[i - n] = nums[i];
            }
            List<Integer> list = new ArrayList();
            for(int i = 0; i < n; i++){
                list.add(a1[i]);
                list.add(a2[i]);
            }
            int[] ar = new int[2*n];
            for(int i = 0; i < 2*n;i++){
                ar[i] = list.get(i);
            }
            return ar;
        }
    }
    class Solution {
        public int[] shuffle(int[] nums, int n) {
            int[] res = new int[2*n];
            for(int i = 0, j = 0; j < n; i += 2){
                res[i] = nums[j];
                res[i+1] = nums[j+n];
                j++;
            }
            return res;
        }
    }
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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/13070127.html
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