Given three integers x
, y
, and bound
, return a list of all the powerful integers that have a value less than or equal to bound
.
An integer is powerful if it can be represented as xi + yj
for some integers i >= 0
and j >= 0
.
You may return the answer in any order. In your answer, each value should occur at most once.
Example 1:
Input: x = 2, y = 3, bound = 10 Output: [2,3,4,5,7,9,10] Explanation: 2 = 20 + 30 3 = 21 + 30 4 = 20 + 31 5 = 21 + 31 7 = 22 + 31 9 = 23 + 30 10 = 20 + 32
Example 2:
Input: x = 3, y = 5, bound = 15 Output: [2,4,6,8,10,14]
Constraints:
1 <= x, y <= 100
0 <= bound <= 106
class Solution { public List<Integer> powerfulIntegers(int x, int y, int bound) { Set<Integer> set = new HashSet(); int a = 1; while(a < bound) { int b = 1; while(b < bound) { if(a + b <= bound) set.add(a + b); if(y == 1) break; b *= y; } if(x == 1) break; a *= x; } return new ArrayList(set); } }
a = a*x,b = b*y。a、b都从1开始。
外循环是a<bound, 内循环是b < bound, 先算内循环的,如果a+b《= bound就添加到set中,但是如果y是1就break,否则剩下的全是11111,如果不是1就更新b。
外循环也一样,如果x是1就直接break,否则就更新a = a*x。
最后返回。