zoukankan      html  css  js  c++  java
  • HDU 1213 How Many Tables(模板——并查集)

    题目链接:

    http://acm.hdu.edu.cn/showproblem.php?pid=1213

    Problem Description
    Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay with strangers.

    One important rule for this problem is that if I tell you A knows B, and B knows C, that means A, B, C know each other, so they can stay in one table.

    For example: If I tell you A knows B, B knows C, and D knows E, so A, B, C can stay in one table, and D, E have to stay in the other one. So Ignatius needs 2 tables at least.
     
    Input
    The input starts with an integer T(1<=T<=25) which indicate the number of test cases. Then T test cases follow. Each test case starts with two integers N and M(1<=N,M<=1000). N indicates the number of friends, the friends are marked from 1 to N. Then M lines follow. Each line consists of two integers A and B(A!=B), that means friend A and friend B know each other. There will be a blank line between two cases.
     
    Output
    For each test case, just output how many tables Ignatius needs at least. Do NOT print any blanks.
     
    Sample Input
    2
    5 3
    1 2
    2 3
    4 5
     
     
    5 1
    2 5
     
    Sample Output
    2
    4
     题意描述:
    输入人数和关系数以及关系
    计算并输出有多少个独立团体
    解题思路:
    处理数据,使用并查集算法即可。
    AC代码:
     1 #include<stdio.h>
     2 void merge(int u,int v);
     3 int getf(int v);
     4 int f[1010];
     5 int main()
     6 {
     7     int T,n,m,a,b,i,sum;
     8     scanf("%d",&T);
     9     while(T--)
    10     {
    11         scanf("%d%d",&n,&m);
    12         for(i=1;i<=n;i++)
    13             f[i]=i;
    14         while(m--)
    15         {
    16             scanf("%d%d",&a,&b);
    17             merge(a,b);
    18         }
    19         
    20         for(sum=0,i=1;i<=n;i++)
    21         {
    22             if(f[i]==i)
    23                 sum++;
    24         }
    25         printf("%d
    ",sum);
    26     }
    27     return 0;
    28 }
    29 void merge(int u,int v)
    30 {
    31     int t1,t2;
    32     t1=getf(u);
    33     t2=getf(v);
    34     if(t1 != t2)
    35         f[t2]=t1;
    36 }
    37 int getf(int v)
    38 {
    39     if(f[v]==v)
    40     return v;
    41     
    42     return f[v]=getf(f[v]);
    43 }
  • 相关阅读:
    20191119PHP.class类练习
    20191115PHP cookie登入实例
    Jenkins详细教程
    Navicat 破解
    测试_离职_交接内容
    ETL方法与过程讲
    ETL测试或数据仓库测试入门
    大数据基础了解-(基础01)
    adb调试显示adb: usage: unknown command device
    hive 创建/删除/截断 表(翻译自Hive wiki)
  • 原文地址:https://www.cnblogs.com/wenzhixin/p/7391205.html
Copyright © 2011-2022 走看看