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  • MySQL

    #先按置顶时间排序,置顶时间为NULL时排在最后,然后按创建时间排序
    SELECT * FROM p_org_share_info
    ORDER BY
        top_time IS NULL ASC, top_time DESC ,create_time DESC
    
    
    
    INSERT INTO c_credit_record
    (
        `id`,`state`,`mobile`,`real_name`,`id_no`,`create_time`,`deadline`,`loan_amount`,`amount`,`bstate` ,`end_date`,`repay_date`
    ) SELECT (SELECT CONCAT((SELECT DATE_FORMAT(NOW(),'%Y%m%d%H%m%s')),(SELECT ROUND(ROUND(RAND(),4)*100000)))) AS id, 
             '24' AS state, 
             mi.`mobile` ,md.`real_name` ,md.`id_no` ,bo.`create_time` ,bo.`deadline` ,bo.`amount` AS loan_amount,bo.`amount`  ,bo.`state` AS bstate,
            (SELECT MAX(end_date) FROM t_repay AS trp WHERE trp.borrow_order_no = bo.borrow_order_no) AS end_date ,
            (SELECT repay_date FROM t_repay WHERE repay_plan_no = (SELECT MAX(repay_plan_no) FROM t_repay_plan WHERE borrow_order_no = bo.borrow_order_no)) AS repay_date 
        FROM 
            `t_memb_i` mi,
            `t_memb_d` md,
            `t_order` bo,
            `t_memb_org_r` mor
        WHERE 
            mi.`member_id` = '1111111111111'
            AND mi.`member_id` = md.`member_id` 
            AND mi.`member_id` = mor.`member_id` 
            AND mor.`member_org_id` = bo.`borrow_member_id` 
    
    
    --比如说,下面这段SQL,你永远无法得到“第二类”这个结果
    CASE WHEN col_1 IN ( 'a', 'b') THEN '第一类'
             WHEN col_1 IN ('a')       THEN '第二类'
    ELSE'其他' END
    
    
    
    --简单Case函数
    CASE sex
             WHEN '1' THEN ''
             WHEN '2' THEN ''
    ELSE '其他' END
    --Case搜索函数
    CASE WHEN sex = '1' THEN ''
             WHEN sex = '2' THEN ''
    ELSE '其他' END

    mysql workbench中PK,NN,UQ,BIN,UN,ZF,AI字段类型标识说明

    PK:primary key 主键
    
    NN:not null 非空
    
    UQ:unique 唯一索引
    
    BIN:binary 二进制数据(比text更大)
    
    UN:unsigned 无符号(非负数)
    
    ZF:zero fill 填充0 例如字段内容是1 int(4), 则内容显示为0001 
    
    AI:auto increment 自增
    #从登陆日志表中查询每个会员最后一次登录的记录
    #https://blog.csdn.net/HXNLYW/article/details/102681680
    SELECT 
      mi.*,
      t1.*
    FROM 
        t_member_info mi,
    
    ( 
    SELECT 
        el.*,
        FROM t_ent_login_log el, (SELECT max(id) id FROM t_ent_login_log group by member_id) md 
        WHERE el.id = md.id
    ) AS t1
    
    WHERE t1.member_id = mi.member_id
    ORDER BY t1.login_time desc ,t1.id
    # 统计每日注册人数和累计注册人数
    SET @i = 0;
    SELECT cc.*,(@i:=@i+cc.当日注册人数) as 累计注册人数
    FROM
    (SELECT date_format(create_time,'%Y-%m-%d') as "日期" , count(*) as "当日注册人数" FROM t_member_info GROUP BY 日期) cc
    CROSS JOIN (select @i:=0) x
    # 查询每天的订单总数及每天的交易成功、交易失败、交易中的订单数
    SELECT
    date_format(create_time,'%Y-%m-%d') as "日期" , count(1) as "当日订单数" , sum(case WHEN apply_status = 6 THEN 1 else 0 end ) 交易成功, sum(case WHEN apply_status = 7 or apply_status = 2 THEN 1 else 0 end ) 交易失败, sum(case WHEN apply_status NOT IN(2,6,7) THEN 1 else 0 end ) 处理中 FROM t_draft_order_apply GROUP BY 日期

    # count(1):统计过滤后所有数据,

    # sum(case WHEN apply_status = 6 THEN 1 else 0 end ) :如果apply_status =6,返回1否则返回0 sum:将返回值进行累加。

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  • 原文地址:https://www.cnblogs.com/weslie/p/6733192.html
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