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  • python中上双互斥锁的线程执行流程

    import threading
    
    def sing():
        print('进入sing -----------------')
        for i in range(3):
            print('进入sing循环 -----------------')
            l1.acquire()
            print('sing上锁 -----------------')
            print('唱歌。。。')
            try:
                print('dance解锁 -----------------')
                l2.release()
                print('dance解锁成功 -----------------')
            except Exception:
                print('sing中dance解锁失败,重新开始循环----------------')
                pass
    
    def dance():
        print('进入dance -----------------')
        for i in range(3):
            print('进入dance循环 -----------------')
            l2.acquire()
            print('dance上锁 -----------------')
            print('跳舞。。。')
            try:
                print('sing解锁 -----------------')
                l1.release()
                print('sing解锁成功 -----------------')
            except Exception:
                print('dance中sing解锁失败,重新开始循环----------------')
                pass
    
    if __name__ == '__main__':
        # sing()
        # dance()
        l1 = threading.Lock()
        print(l1)
        l2 = threading.Lock()
        print(l2)
        t1 = threading.Thread(target=sing)
        t2 = threading.Thread(target=dance)
        print('线程创建完毕--------')
        t1.start()
        print('线程1开始执行------')
        t2.start()
        print('线程2开始执行------')
        t1.join()
        print('线程1守护主线程-----')
        t2.join()
        print('线程2守护主线程-----')
    

      

      

      这里我们暂且先不提全局解释器锁,从这个代码例子里我们可以看出,一个锁在上锁以后,如果在没有释放它的情况下再要对它上锁,他就会阻塞住,一直到它的锁被释放了以后才能够再次被上锁,这样就实现了两个线程的交替执行。

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  • 原文地址:https://www.cnblogs.com/wf-skylark/p/9104647.html
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