函数式编程reduce

# num=[1,2,3,4,5]
# res=0
# for i in num:
#     res+=num
# print(res)

# def reduce_test(array):
#     res=0
#     for i in array:
#         res=num+1
#     return res
# print(reduce_test(num))

# def multi(x,y):
#     return x*y
# lambda x,y:x*y

# def reduce_test(func,array,init=None):
#     if init is None:
#         res=array.pop(0)#列表传过来先拿第一个值用pop函数实现
#     else:
#         res=init
#     for i in array:
#          res*=func(res,num)
#     return res
# print(reduce_test(lambda x,y:x*y,num,100))#传送的是函数和Num列表
#map原有数据处理一遍，reduce数据压缩一下合并成一个序列最后得到一个结果
#reduce函数需要先导入
from functools import reduce
num=[1,2,3,100]
print(reduce(lambda x,y:x+y,num,10))

结果116=10+1+2+3+100