POJ 1451 T9 字典树+优先队列

题目来源：POJ 1451 T9

题意：给你一些单词 和优先值 然后当你按下数字的时候首先会出现哪个单词 就是我们平时手机的按键

思路：建一颗字典树 由于按一个数字相应多个字母 那么就有多种情况 我们要输出权值最大的一个 我用了优先队列 这里每一个前缀的优先值是全部单词优先值的和

比如abc 5 abd 6 acd 7 那么a这个前缀的优先值是18 ab的优先值是11

#include <cstdio>
#include <cstring>
#include <queue>
using namespace std;
const int maxnode = 100010;
const int sigma_size = 26;
const int maxn = 1010;
int ch[maxnode][sigma_size];
int val[maxnode];
int sz;

char s[maxn][110];
char id[12][6] = {"0", "1", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"};
void init()
{
	sz = 1;
	memset(ch[0], 0, sizeof(ch[0]));
}
struct node
{
	int u, v, x;
	char str[110];
	node(){}
	node(int _u, int _v, int _x, char* s)
	{
		u = _u;
		v = _v;
		x = _x;
		strcpy(str, s);
	}
	bool operator < (const node& rhs) const
	{
		if(v != rhs.v)
			return v > rhs.v;
		return x < rhs.x;
	}
};
int idx(char c)
{
	if(c >= 'a' && c <= 'c')
		return 2;
	if(c >= 'd' && c <= 'f')
		return 3;
	if(c >= 'g' && c <= 'i')
		return 4;
	if(c >= 'j' && c <= 'l')
		return 5;
	if(c >= 'm' && c <= 'o')
		return 6;
	if(c >= 'p' && c >= 's')
		return 7;
	if(c >= 't' && c <= 'v')
		return 8;
	if(c >= 'w' && c <= 'z')
		return 9;
}

void insert(char *s, int v)
{
	int u = 0, n = strlen(s);
	for(int i = 0; i < n; i++)
	{
		int c = s[i] - 'a';
		if(!ch[u][c])
		{
			memset(ch[sz], 0, sizeof(ch[sz]));
			val[sz] = 0;
			ch[u][c] = sz++;
		}
		u = ch[u][c];
		val[u] += v;
	}
	//val[u] += v;
}
void find(char *s)
{
	int u = 0, n = strlen(s);
	priority_queue <node> Q;
	Q.push(node(0, 0, 0, ""));
	for(int i = 0; i < n-1; i++)
	{
		int c = s[i]-'0';
		while(!Q.empty())
		{
			node x = Q.top();
			if(x.v != i)
				break;
			Q.pop();
			u = x.u;
			
			for(int j = 0; id[c][j]; j++)
			{
				int v = id[c][j] - 'a';
				//printf("%d
", v);
				if(!ch[u][v])
					continue;
				v = ch[u][v];
				x.str[i] = id[c][j];
				x.str[i+1] = 0;
				//printf("%c
", id[c][j]);
				Q.push(node(v, i+1, val[v], x.str));
			}
		}
		if(Q.empty())
		{
			puts("MANUALLY");
		}
		else
		{
			node x = Q.top();
			printf("%s
", x.str);
		}
	}
}

int main()
{
	int cas = 1;
	int T;
	scanf("%d", &T);
	while(T--)
	{
		int n, m;
		scanf("%d", &n);
		init();
		for(int i = 0; i < n; i++)
		{
			//char s[maxn];
			int x;
			scanf("%s %d", s[i], &x);
			insert(s[i], x);
		}
		printf("Scenario #%d:
", cas++);
		scanf("%d", &m);
		while(m--)
		{
			char str[210];
			scanf("%s", str);
			find(str);
			puts("");
		}
		puts("");
	}
	return 0;
}