Given an array A of 0s and 1s, consider N_i: the i-th subarray from A[0] to A[i] interpreted as a binary number (from most-significant-bit to least-significant-bit.)
Return a list of booleans answer, where answer[i] is true if and only if N_i is divisible by 5.
一个二进制数组,问A[0]-A[i]组成的子数组,是否能被5整除。
能被5整除的数只需要看最后一位是不是5或者0就行。
class Solution(object): def prefixesDivBy5(self, A): """ :type A: List[int] :rtype: List[bool] """ ans = [] num = 0 for value in A: num <<= 1 num += value num %= 10 ans.append(num % 5 == 0) return ans