两根指 针
1. 一个数组,从两边往中间移动(对撞型)
2. 一个数组,同时向前移动(前向型)
3. 两个数组(并行型)
对 撞型或者相会型 Two sum 类 和 Partition 类
1 Two Sum
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public int[] twoSum(int[] numbers, int target) { if (numbers == null || numbers.length < 2) { return null; } int[] res = new int[2]; HashMap<Integer, Integer> map = new HashMap<Integer, Integer>(); for (int i = 0; i < numbers.length; i++) { if (map.containsKey(target - numbers[i])) { res[0] = map.get(target - numbers[i]) + 1; res[1] = i + 1; return res; } map.put(numbers[i], i); } return r
2 Two Sum - Input array is sorted
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public int[] twoSum(int[] nums, int target) { // write your code here int[] res = new int[]{-1, -1}; if (nums == null || nums.length == 0) { return res; } int left = 0; int right = nums.length - 1; while (left < right) { int sum = nums[left] + nums[right]; if (sum == target) { res[0] = left + 1; res[1] = right + 1; return res; } else if (sum > target) { right--; } else { left++; } } return res; }
3 Triangle Count
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public int triangleCount(int s[]) { if (s == null || s.length < 3) { return 0; } int res = 0; Arrays.sort(s); for (int i = s.length - 1; i >= 2; i--) { int left = 0; int right = i - 1; while (left < right) { if (s[left] + s[right] > s[i]) { res += right - left; right--; } else { left++; } } } return res; }
4 Trapping Rain Water
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public int trapRainWater(int[] heights) { if (heights == null || heights.length == 0) { return 0; } int res = 0; int l = 0; int r = heights.length - 1; int left_height = heights[l]; int right_height = heights[r]; while (l < r) { if (left_height < right_height) { l++; if (left_height > heights[l]) { res += left_height - heights[l]; } else { left_height = heights[l]; } } else { r--; if (right_height > heights[r]) { res += right_height - heights[r]; } else { right_height = heights[r]; } } } return res; }
5 Container With Most Water
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public int maxArea(int[] heights) { // write your code here if (heights == null && heights.length == 0) { return 0; } int l = 0; int r = heights.length - 1; int maxArea = 0; while (l < r) { maxArea = Math.max(maxArea, Math.min(heights[l], heights[r])*(r - l)); if (heights[l] < heights[r]) { l++; } else { r--; } } return maxArea; }
6 Kth Largest Element
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public class Solution { /* * @param : An integer * @param : An array * @return: the Kth largest element */ public int kthLargestElement(int n, int[] nums) { // write your code here if (nums == null || n <= 0 || n > nums.length) { return -1; } n = nums.length - n; return find(nums, n, 0, nums.length - 1); } int find(int[] nums, int n, int l, int r) { if (l == r) { return nums[l]; } int index = partion(nums, l, r); if (n == index) { return nums[n]; } else if (n > index) { return find(nums, n, index + 1, r); } else { return find(nums, n, l, index - 1); } } int partion(int[] nums, int l, int r) { int x = nums[r]; int j = l - 1; for (int i = l; i < r; i++) { if (nums[i] <= x) { j++; swap(nums, j, i); } swap(nums, j + 1, r); } return j; } void swap(int[] nums, int l, int r) { int temp = nums[l]; nums[l] = nums[r]; nums[r] = temp; } };
7 Nuts & Bolts Problem
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public void sortNutsAndBolts(String[] nuts, String[] bolts, NBComparator compare) { // write your code here sort(nuts, bolts, 0, nuts.length - 1, compare); } public void sort(String[] nuts, String[] bolts, int l, int r, NBComparator compare){ if (l >= r) { return; } int index = partion(nuts, bolts[r], l, r, compare); partion(bolts, nuts[index], l, r, compare); sort(nuts, bolts, l, index - 1, compare); sort(nuts, bolts, index + 1, r, compare); } public int partion(String[] strs, String str, int l, int r, NBComparator compare) { for (int i = l; i <= r; i++) { if (compare.cmp(strs[i], str) == 0 || compare.cmp(str, strs[i]) == 0) { swap(strs, i, r); break; } } int i = l - 1; for (int j = l; j < r; j++) { if (compare.cmp(strs[j], str) == -1 || compare.cmp(str, strs[j]) == 1) { i++; swap(strs, i, j); } } swap(strs, i + 1, r); return i + 1; } public void swap(String[] strs, int l, int r){ String item = strs[l]; strs[l] = strs[r]; strs[r] = item; } };
前向型或者追 击 窗口类 和 快慢类
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窗口 类 指 针 移 动 模板 通过两层for循环改进算法 ---------------不同于sliding window for (i =0; i < n; i++) while(j < n){ if(满足条件) j++; 更新j状态 else(不满足条件) break; } 更新i状态 } 与sliding windows 区别 ?
1 Longest Substring Without Repeating Characters
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public int lengthOfLongestSubstring(String s) { if(s==null || s.length()==0) { return 0; } int[] num = new int[256]; int max = 1; for (int i = 0, j = 0; i < s.length(); i++) { while (j < s.length() && num[s.charAt(j)] == 0) { num[s.charAt(j)] = 1; max = Math.max(max, j - i + 1); j++; } num[s.charAt(i)] = 0; } return max; }
2 Minimum Size Subarray Sum
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public int minimumSize(int[] nums, int s) { // write your code here if (nums == null || nums.length == 0) { return -1; } int min = Integer.MAX_VALUE; int sum = 0; for (int i = 0, j = 0; i < nums.length; i++) { while (j < nums.length && sum < s) { sum += nums[j]; j++; } if (sum >= s) { min = Math.min(min, j - i); } sum -= nums[i]; } if (min == Integer.MAX_VALUE) { return -1; } return min; }
3 Minimum Window Substring
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int initTarget(int[] target, String targetWord) { int count = 0; for (char c : targetWord.toCharArray()) { target[c]++; count++; } return count; } boolean isValid(int[] target, int[] source) { for (int i = 0; i < 256; i++) { if (target[i] > source[i]) { return false; } } return true; } public String minWindow(String s, String t) { int min = Integer.MAX_VALUE; String res = ""; int[] source = new int[256]; int[] target = new int[256]; initTarget(target, t); for (int i = 0, j = 0; i < s.length(); i++) { while (j < s.length() && !isValid(target, source)) { source[s.charAt(j)]++; j++; } if (isValid(target, source)) { if (min > j - i) { min = j - i; res = s.substring(i, j); } } source[s.charAt(i)]--; } return res; }
4 Longest Substring with At Most Two Distinct Characters
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public int lengthOfLongestSubstringKDistinct(String s, int k){ if (s == null || s.length() == 0 || k <= 0) { return -1; } Map<Character, Integer> map = new HashMap<>(); int max = 0; for (int i = 0, j = 0; i < s.length(); i++) { while (j < s.length() && (map.size() == k && map.containsKey(s.charAt(j)) || map.size() < k && !map.containsKey(s.charAt(j)))) { if (map.containsKey(s.charAt(j))) { map.put(s.charAt(j), map.get(s.charAt(j)) + 1); } else { map.put(s.charAt(j), 1); } } max = Math.max(max, map.size()); if (map.get(s.charAt(i)) == 1) { map.remove(s.charAt(i)); } else { map.put(s.charAt(i), map.get(s.charAt(i)) - 1); } } return max; }
5 The Smallest Difference
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public int smallestDifference(int[] a, int[] b) { // write your code here if (a == null || a.length == 0 || b == null || b.length == 0) { return 0; } int res = Integer.MAX_VALUE; for (int i = 0, j = 0; i < a.length && j < b.legnth;) { res = Math.min(res, Math.abs(a[i] - b[j])); if (a[i] > b[j]) { j++; } else { i++; } } return res; }