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  • leetcode 6. ZigZag Conversion [java]

    自己写的:

    if(numRows == 1)   return s;
            int ll = s.length() / 2 + 1;
            Character tc[] = new Character[numRows* ll];
            int i = 0, j = 0;
            boolean down = true;
            for(int k = 0; k < s.length(); k++){
                tc[i* ll + j] = s.charAt(k);
                if(down){
                    i++;
                    if(i == numRows){
                        i -= 2;
                        j ++;
                        down = false;
                    }
                }else{
                    i--;
                    j++;
                    if(i == -1){
                        i = 1;
                        j --;
                        down = true;
                    }
                }
            }
            String res = "";
            for(i=0;i < tc.length; i ++){
                if(tc[i] != null)
                    res += tc[i]; 
            }
            return res;
    

    参考于discuss:

    char[] c = s.toCharArray();
            int len = c.length;
            StringBuffer[] sb = new StringBuffer[numRows];
            for (int i = 0; i < sb.length; i++) sb[i] = new StringBuffer();
            
            int i = 0;
            while(i < len){
                for (int idx = 0; idx < numRows&&i < len; idx ++)
                    sb[idx].append(c[i++]);
                for (int idx = numRows -2; idx >= 1 && i < len; idx --)
                    sb[idx].append(c[i++]);
            }
            for(int idx = 1;idx < sb.length; idx ++)
                sb[0].append(sb[idx]);
            return sb[0].toString();
    
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  • 原文地址:https://www.cnblogs.com/whyaza/p/10661098.html
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