zoukankan      html  css  js  c++  java
  • (简单) POJ 2251 Dungeon Master,BFS。

      Description

      You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move diagonally and the maze is surrounded by solid rock on all sides.

      Is an escape possible? If yes, how long will it take?

      一个三维的迷宫问题,和二维没什么区别,直接BFS就好。

    代码如下:

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<queue>
    
    using namespace std;
    
    bool map1[40][40][40];
    bool vis[40][40][40];
    int L,R,C;
    int Sl,Sr,Sc,El,Er,Ec;
    
    struct state
    {
        int l,r,c;
        int num;
    
        state() {}
        state(int x,int y,int z,int n):l(x),r(y),c(z),num(n) {}
    };
    
    bool judge(int x,int y,int z)
    {
        if(x<=0||x>L||y<=0||y>R||z<=0||z>C)
            return 0;
    
        if(map1[x][y][z]==0)
            return 0;
    
        if(vis[x][y][z])
            return 0;
    
        vis[x][y][z]=1;
        return 1;
    }
    
    int bfs()
    {
        queue <state> que;
        state temp;
        int tl,tr,tc;
    
        que.push(state(Sl,Sr,Sc,0));
    
        while(!que.empty())
        {
            temp=que.front();
            que.pop();
    
            if(temp.l==El&&temp.r==Er&&temp.c==Ec)
                return temp.num;
    
            tl=temp.l;
            tr=temp.r;
            tc=temp.c;
    
            if(judge(tl-1,tr,tc))
                que.push(state(tl-1,tr,tc,temp.num+1));
            if(judge(tl+1,tr,tc))
                que.push(state(tl+1,tr,tc,temp.num+1));
            if(judge(tl,tr-1,tc))
                que.push(state(tl,tr-1,tc,temp.num+1));
            if(judge(tl,tr+1,tc))
                que.push(state(tl,tr+1,tc,temp.num+1));
            if(judge(tl,tr,tc-1))
                que.push(state(tl,tr,tc-1,temp.num+1));    
            if(judge(tl,tr,tc+1))
                que.push(state(tl,tr,tc+1,temp.num+1));
        }
    
        return -1;
    }
    
    int main()
    {
        char s[50];
        int ans;
    
        ios::sync_with_stdio(false);
    
        while(cin>>L>>R>>C)
        {
            memset(vis,0,sizeof(vis));
    
            if(!L&&!R&&!C)
                break;
    
            for(int i=1;i<=L;++i)
                for(int j=1;j<=R;++j)
                {
                    cin>>s;
                    for(int k=1;k<=C;++k)
                        switch(s[k-1])
                        {
                            case 'S':
                                Sl=i;
                                Sr=j;
                                Sc=k;
                                map1[i][j][k]=1;
                                break;
                            case 'E':
                                El=i;
                                Er=j;
                                Ec=k;
                                map1[i][j][k]=1;
                                break;
                            case '.':
                                map1[i][j][k]=1;
                                break;
                            case '#':
                                map1[i][j][k]=0;
                                break;
                        }
                }
    
            ans=bfs();
    
            if(ans!=-1)
                cout<<"Escaped in "<<ans<<" minute(s).
    ";
            else
                cout<<"Trapped!
    ";
        }
    
        return 0;
    }
    View Code
  • 相关阅读:
    ASP.NET 概述
    用vs调试项目页面无样式
    eniac世界第二台计算机
    汇编语言
    操作系统发展史
    网站架构发展
    简单分布式系统构建知识
    Android常用adb命令
    USB 3.0规范中译本 第4章 超高速数据流模型
    ECMAScript 6 &ECMAScript 5(在线手册)
  • 原文地址:https://www.cnblogs.com/whywhy/p/4228073.html
Copyright © 2011-2022 走看看