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  • 算法笔记--圆方树

    模板:

    struct Circle_Square_Tree {
        const static int N = 2e4 + 10;
        vector<pair<int, LL> > G[N];
        int dp[N], anc[N][18], n;
        LL dis[N], cir[N]; //环的大小
        bool vis[N];//记录到方点的最短距离是否经过回边
    
        vector<pii> g[N];
        int dfn[N], low[N], fa[N], cnt, tot;
        int a[N];
        inline void solve(int u, int v, int d) {
            int cnt = 0;
            LL sum = d;
            for (int i = v; i != u; i = fa[i]) sum += dis[i] - dis[fa[i]], a[++cnt] = i;
            a[++cnt] = u;
            LL DIS = 0;
            ++tot;
            for (int i = cnt; i >= 1; --i) {
                LL D = min(DIS, sum-DIS);
                if(D == DIS) vis[a[i]] = true;
                else vis[a[i]] = false;
                G[a[i]].pb({tot, D});
                G[tot].pb({a[i], D});
                DIS += dis[a[i-1]]-dis[a[i]];
            }
            cir[tot] = sum;
        }
        inline void tarjan(int u, int o) {
            fa[u] = o;
            dfn[u] = low[u] = ++cnt;
            for (int i = 0; i < g[u].size(); ++i) {
                int v = g[u][i].fi;
                int w = g[u][i].se;
                if(v == o) continue;
                if(!dfn[v]) {
                    dis[v] = dis[u] + w;
                    tarjan(v, u);
                    low[u] = min(low[u], low[v]);
                }
                else low[u] = min(low[u], dfn[v]);
                if(low[v] > dfn[u]) {
                    G[u].pb({v, w});
                    G[v].pb({u, w});
                }
            }
            for (int i = 0; i < g[u].size(); ++i) {
                int v = g[u][i].fi;
                int w = g[u][i].se;
                if(v == o) continue;
                if(fa[v] != u && dfn[v] > dfn[u]) {
                    solve(u, v, w);
                }
            }
        }
        inline void dfs(int u, int o) {
            anc[u][0] = o;
            dp[u] = dp[o] + 1;
            for (int i = 1; i < 18; ++i) anc[u][i] = anc[anc[u][i-1]][i-1];
            for (int i = 0; i < G[u].size(); ++i) {
                int v = G[u][i].fi;
                LL w = G[u][i].se;
                if(v == o) continue;
                dis[v] = dis[u] + w;
                dfs(v, u);
            }
        }
        inline void init(int _n) {
            tot = n = _n;
            cnt = 0;
            dis[0] = dp[1] = 0;
            tarjan(1, 0);
            dfs(1, 1);
        }
        inline int lca(int u, int v) {
            if(dp[u] < dp[v]) swap(u, v);
            for (int i = 17; i >= 0; --i) if(dp[anc[u][i]] >= dp[v]) u = anc[u][i];
            if(u == v) return u;
            for (int i = 17; i >= 0; --i) if(anc[u][i] != anc[v][i]) u = anc[u][i], v = anc[v][i];
            return anc[u][0];
        }
        inline int jump(int u, int lca) {
            for (int i = 17; i >= 0; --i) if(dp[anc[u][i]] > dp[lca]) u = anc[u][i];
            return u;
        }
        inline LL query(int u, int v) {
            int l = lca(u, v);
            if(l <= n) return dis[u]+dis[v]-2*dis[l];
            int uu = jump(u, l), vv = jump(v, l);
            LL d1 = dis[uu]-dis[l], d2 = dis[vv]-dis[l];
            if(!vis[uu]) d1 = cir[l]-d1;
            if(!vis[vv]) d2 = cir[l]-d2;
            return dis[u]-dis[uu]+dis[v]-dis[vv]+min(abs(d1-d2), cir[l]-abs(d1-d2));
        }
    }CST;
    
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  • 原文地址:https://www.cnblogs.com/widsom/p/11468827.html
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