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      1 #include <stdio.h>
      2 #include <algorithm>
      3 #include <iostream>
      4 #include <string.h>
      5 using namespace std;
      6 const int MAXN = 1010;
      7 int tree[20][MAXN];
      8 int sorted[MAXN];
      9 int toleft[20][MAXN];
     10 long long sum[20][MAXN];
     11 
     12 void build(int l,int r,int dep)
     13 {
     14     if(l == r)
     15     {
     16         sum[dep][l] = sum[dep][l-1]+tree[dep][l];
     17         return;
     18     }
     19     int mid = (l+r)>>1;
     20     int same = mid - l + 1;
     21     for(int i = l; i <= r; i++)
     22     {
     23         if(tree[dep][i] < sorted[mid])
     24             same--;
     25         sum[dep][i] += sum[dep][i-1]+tree[dep][i];
     26     }
     27     int lpos = l;
     28     int rpos = mid+1;
     29     for(int i = l; i <= r; i++)
     30     {
     31         if(tree[dep][i] < sorted[mid])
     32             tree[dep+1][lpos++] = tree[dep][i];
     33         else if(tree[dep][i] == sorted[mid] && same > 0)
     34         {
     35             tree[dep+1][lpos++] = tree[dep][i];
     36             same--;
     37         }
     38         else
     39             tree[dep+1][rpos++] = tree[dep][i];
     40         toleft[dep][i] = toleft[dep][l-1] + lpos - l;
     41     }
     42     build(l,mid,dep+1);
     43     build(mid+1,r,dep+1);
     44 }
     45 long long ans;
     46 int query(int L,int R,int l,int r,int dep,int k)
     47 {
     48     if(l == r)return tree[dep][l];
     49     int mid = (L+R)>>1;
     50     int cnt = toleft[dep][r] - toleft[dep][l-1];
     51     if(cnt >= k)
     52     {
     53         int ee = r-L+1-(toleft[dep][r]-toleft[dep][L-1])+mid;
     54         int ss = l-L-(toleft[dep][l-1]-toleft[dep][L-1])+mid;
     55         ans += sum[dep+1][ee]-sum[dep+1][ss];
     56         int newl = L + toleft[dep][l-1]-toleft[dep][L-1];
     57         int newr = newl + cnt -1;
     58         return query(L,mid,newl,newr,dep+1,k);
     59     }
     60     else
     61     {
     62         int s = L + toleft[dep][l-1] - toleft[dep][L-1];
     63         int e = s + cnt - 1;
     64         ans -= sum[dep+1][e] - sum[dep+1][s-1];
     65         int newr = r + toleft[dep][R] - toleft[dep][r];
     66         int newl = newr - (r-l+1-cnt) + 1;
     67         return query(mid+1,R,newl,newr,dep+1,k-cnt);
     68     }
     69 }
     70 int main()
     71 {
     72     int T;
     73     int n;
     74     scanf("%d",&T);
     75     int iCase = 0;
     76     while(T--)
     77     {
     78         iCase++;
     79         scanf("%d",&n);
     80         memset(tree,0,sizeof(tree));
     81         memset(sum,0,sizeof(sum));
     82         for(int i = 1; i <= n; i++)
     83         {
     84             scanf("%d",&tree[0][i]);
     85             sorted[i] = tree[0][i];
     86         }
     87         sort(sorted+1,sorted+n+1);
     88         build(1,n,0);
     89         printf("Case #%d:
    ",iCase);
     90         int m,l,r;
     91         scanf("%d",&m);
     92         while(m--)
     93         {
     94             scanf("%d%d",&l,&r);
     95             l++;
     96             r++;
     97             ans = 0;
     98             int tmp = query(1,n,l,r,0,(l+r)/2-l+1);
     99             if((l+r)%2)ans-=tmp;
    100             printf("%lld
    ",ans);
    101         }
    102         printf("
    ");
    103     }
    104     return 0;
    105 }
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  • 原文地址:https://www.cnblogs.com/wkfvawl/p/9447537.html
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