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  • HDu 1001 Sum Problem 分类: ACM 2015-06-19 23:38 12人阅读 评论(0) 收藏

    Sum Problem

    Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 338086    Accepted Submission(s): 85117


    Problem Description
    Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

    In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
     

    Input
    The input will consist of a series of integers n, one integer per line.
     

    Output
    For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
     

    Sample Input
    1 100
     

    Sample Output
    1 5050
     

    Author
    DOOM III
     

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    这题其实没有想象的那么简单,要注意先除后乘这样不会爆掉,所以还要考虑奇偶,不过还有种办法是用double存,最后强转回int 也可以

    #include<queue>
    #include<math.h>
    #include<stdio.h>
    #include<string.h>
    #include<iostream>
    #include<algorithm>
    using namespace std;
    #define N 115


    int main()
    {
        int n;
        __int64 w;
        while(~scanf("%d",&n))
        {
            if(n%2==0) w=n/2*(n+1);
            else w=(n+1)/2*n;
            printf("%I64d ",w);
        }




        return 0;
    }








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  • 原文地址:https://www.cnblogs.com/wmxl/p/4662700.html
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