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  • 项目总结31:Java字符串过滤特殊字符和表情符号

    项目总结31:Java字符串过滤特殊字符和表情符号

     

    直接上源码

    package com.hs.common.util.emojifilter;
    
    import org.apache.commons.lang3.StringUtils;
    
    public class EmojiFilter {
        /**
         * 检测是否有emoji字符
         * @param source
         * @return 一旦含有就抛出
         */
        public static boolean containsEmoji(String source) {
            if (StringUtils.isBlank(source)) {
                return false;
            }
    
            int len = source.length();
    
            for (int i = 0; i < len; i++) {
                char codePoint = source.charAt(i);
    
                if (isEmojiCharacter(codePoint)) {
                    //do nothing,判断到了这里表明,确认有表情字符
                    return true;
                }
            }
    
            return false;
        }
    
        private static boolean isEmojiCharacter(char codePoint) {
            return (codePoint == 0x0) ||
                    (codePoint == 0x9) ||
                    (codePoint == 0xA) ||
                    (codePoint == 0xD) ||
                    ((codePoint >= 0x20) && (codePoint <= 0xD7FF)) ||
                    ((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) ||
                    ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));
        }
    /**
         * 过滤emoji 或者 其他非文字类型的字符
         * @param source
         * @return
         */
        public static String filterEmoji(String source) {
    
            if (!containsEmoji(source)) {
                return source;//如果不包含,直接返回
            }
            //到这里铁定包含
            StringBuilder buf = null;
    
            int len = source.length();
    
            for (int i = 0; i < len; i++) {
                char codePoint = source.charAt(i);
    
                if (isEmojiCharacter(codePoint)) {
                    if (buf == null) {
                        buf = new StringBuilder(source.length());
                    }
    
                    buf.append(codePoint);
                } else {
                }
            }
    
            if (buf == null) {
                return source;//如果没有找到 emoji表情,则返回源字符串
            } else {
                if (buf.length() == len) {//这里的意义在于尽可能少的toString,因为会重新生成字符串
                    buf = null;
                    return source;
                } else {
                    return buf.toString();
                }
            }
    
        }
    }

     

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  • 原文地址:https://www.cnblogs.com/wobuchifanqie/p/11059226.html
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