HDU 1004 Let the Balloon Rise（STL初体验之map）

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you. 

 

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

 

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

 

Sample Input

5 green red blue red red 3 pink orange pink 0

 

Sample Output

red pink

题目大意：如题

思路：创建一个map<string, int>， 通过cnt["string"]=int的方法储存值，学习其中关于“找a是否存在，不存在就先让它为0，再加1，存在就直接加一”

代码如下

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
#include<string>
#include<set>
#include<map>
#include<queue>
#include<cmath>
#include<stdlib.h>
typedef long long ll;
typedef unsigned long long ull;
using namespace std;
const int maxn = 1e5 + 100;
double eps = 1e-8;
map<string, int> cnt;
int main(){
	int n;
	while(scanf("%d", &n) && n){
		cnt.clear();
		string a;
		int ans =0;
		string anss;
		for(int i = 0; i < n ; i++){
			cin >> a;
			if(!cnt.count(a))cnt[a]=0;
			cnt[a]++;
			if(cnt[a]>ans){
				ans =cnt[a];
				anss = a;
			}
		}
		cout << anss << endl;
		
	}
	
    return 0;
}