Write a program to solve a Sudoku puzzle by filling the empty cells.
A sudoku solution must satisfy all of the following rules:
- Each of the digits
1-9
must occur exactly once in each row. - Each of the digits
1-9
must occur exactly once in each column. - Each of the digits
1-9
must occur exactly once in each of the 93x3
sub-boxes of the grid.
The '.'
character indicates empty cells.
Example 1:
Input: board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]] Output: [["5","3","4","6","7","8","9","1","2"],["6","7","2","1","9","5","3","4","8"],["1","9","8","3","4","2","5","6","7"],["8","5","9","7","6","1","4","2","3"],["4","2","6","8","5","3","7","9","1"],["7","1","3","9","2","4","8","5","6"],["9","6","1","5","3","7","2","8","4"],["2","8","7","4","1","9","6","3","5"],["3","4","5","2","8","6","1","7","9"]] Explanation: The input board is shown above and the only valid solution is shown below:
Constraints:
board.length == 9
board[i].length == 9
board[i][j]
is a digit or'.'
.- It is guaranteed that the input board has only one solution.
class Solution { public: void solveSudoku(vector<vector<char>>& board) { help(board); return; } //回溯 bool help(vector<vector<char>>& board){ for(int i=0;i<board.size();i++){ for(int j=0;j<board[i].size();j++){ //最后没有数字要填,退出递归 if(board[i][j] == '.'){ for(char k='1';k<='9';k++){ //先判定有效再填入 if(isValid(board,i,j,k)){ board[i][j] = k; if(help(board)) return true; else board[i][j] = '.'; } } //所有数字都填了 return false; } //没有数字要填了,退出返回true } } return true; } private: //填入的c(1-9)在该行、该列、以及该box中是否有效,有效才填入,无效换下一个数 bool isValid(vector<vector<char>>& board,int row,int col,char c){ for(int i=0;i<9;i++){ if(c == board[row][i]) return false; if(c == board[i][col]) return false; int x = i/3+row/3*3;
//不好想到 int y = i%3+col/3*3; if(c == board[x][y]) return false; } return true; } };