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  • Remove Duplicates from Sorted List

    Given a sorted linked list, delete all duplicates such that each element appear only once.

    For example,
    Given 1->1->2, return 1->2.
    Given 1->1->2->3->3, return 1->2->3.

    采用头插法实现顺序插入,C++代码如下:

    #include<iostream>
    #include<new>
    using namespace std;
    
    //Definition for singly-linked list.
    struct ListNode
    {
        int val;
        ListNode *next;
        ListNode(int x) : val(x), next(NULL) {}
    };
    class Solution
    {
    public:
        ListNode *deleteDuplicates(ListNode *head)
        {
            ListNode *pp=NULL;
            ListNode *p=NULL;
            ListNode *q=NULL;
            if(head&&head->next)
            {
                pp=head;
                p=head->next;
                while(p)
                {
                    if(pp->val==p->val)
                    {
                        q=p;
                        pp->next=q->next;
                        p=q->next;
                        delete q;
                    }
                    else
                    {
                        pp=p;
                        p=p->next;
                    }
                }
            }
            return head;
        }
        void createList(ListNode *&head)
        {
            ListNode *p=NULL;
            int i=0;
            int arr[10]= {5,5,5,4,4,3,3,3,2,1};
            for(i=0; i<10; i++)
            {
                if(head==NULL)
                {
                    head=new ListNode(arr[i]);
                    if(head==NULL)
                        return;
                }
                else
                {
                    p=new ListNode(arr[i]);
                    p->next=head;
                    head=p;
                }
            }
        }
    };
    
    int main()
    {
        Solution s;
        ListNode *L=NULL;
        s.createList(L);
        ListNode *head=L;
        while(head)
        {
            cout<<head->val<<" ";
            head=head->next;
        }
        cout<<endl;
        L=s.deleteDuplicates(L);
        while(L)
        {
            cout<<L->val<<" ";
            L=L->next;
        }
    }

    运行结果:

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  • 原文地址:https://www.cnblogs.com/wuchanming/p/4096426.html
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