Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
采用头插法实现顺序插入,C++代码如下:
#include<iostream> #include<new> using namespace std; //Definition for singly-linked list. struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; class Solution { public: ListNode *deleteDuplicates(ListNode *head) { ListNode *pp=NULL; ListNode *p=NULL; ListNode *q=NULL; if(head&&head->next) { pp=head; p=head->next; while(p) { if(pp->val==p->val) { q=p; pp->next=q->next; p=q->next; delete q; } else { pp=p; p=p->next; } } } return head; } void createList(ListNode *&head) { ListNode *p=NULL; int i=0; int arr[10]= {5,5,5,4,4,3,3,3,2,1}; for(i=0; i<10; i++) { if(head==NULL) { head=new ListNode(arr[i]); if(head==NULL) return; } else { p=new ListNode(arr[i]); p->next=head; head=p; } } } }; int main() { Solution s; ListNode *L=NULL; s.createList(L); ListNode *head=L; while(head) { cout<<head->val<<" "; head=head->next; } cout<<endl; L=s.deleteDuplicates(L); while(L) { cout<<L->val<<" "; L=L->next; } }
运行结果: