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  • 202. Happy Number(LeetCode)

    Write an algorithm to determine if a number is "happy".

    A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

    Example: 19 is a happy number

    • 12 + 92 = 82
    • 82 + 22 = 68
    • 62 + 82 = 100
    • 12 + 02 + 02 = 1
       1 class Solution {
       2 public:
       3    int fang(int n)
       4     {
       5         int sum = 0;
       6         while (n != 0)
       7         {
       8             sum += (n % 10)*(n % 10);
       9             n = n / 10;
      10         }
      11         cout<<sum<<endl;
      12         return sum;
      13     }
      14     
      15     bool isHappy(int n) {
      16         int i=0;
      17             while (n!=1&&i<100)
      18             {
      19                 n = fang(n);
      20                 cout<<n<<endl;
      21                 i++;
      22             }
      23             if (n == 1&&i<100)
      24             {
      25                 return true;
      26             }
      27             if (i >= 100)
      28             return false;
      29     }
      30 };
       1 class Solution {
       2 public:
       3     bool isHappy(int n) {
       4         unordered_map<int, bool> m;
       5         while (n != 1 && !m.count(n)){
       6             m[n] = true;
       7             int new_n = 0;
       8             while (n){
       9                 new_n += (n % 10)*(n % 10);
      10                 n /= 10;
      11             }
      12             n = new_n;
      13         }
      14         return n == 1;
      15     }
      16 };
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  • 原文地址:https://www.cnblogs.com/wujufengyun/p/6855722.html
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