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  • 605. Can Place Flowers(LeetCode)

    Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.

    Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.

    Example 1:

    Input: flowerbed = [1,0,0,0,1], n = 1
    Output: True
    

    Example 2:

    Input: flowerbed = [1,0,0,0,1], n = 2
    Output: False
    

    Note:

    1. The input array won't violate no-adjacent-flowers rule.
    2. The input array size is in the range of [1, 20000].
    3. n is a non-negative integer which won't exceed the input array size.
       1     class Solution {
       2     public:
       3         bool canPlaceFlowers(vector<int>& flowerbed, int n) {
       4         int count = 0;
       5         int len = flowerbed.size();
       6         vector<int> vet(len+2, 0);
       7         for (int i = 0; i < len; i++)
       8         {
       9             vet[i+1]=(flowerbed[i]);
      10         }
      11         for (int i = 0; i < len; i++)
      12         {
      13             if (vet[i] == 0 && vet[i + 1] == 0 && vet[i + 2] == 0)
      14             {
      15                 count++;
      16                 vet[i+1]=1;
      17             }
      18         }
      19         //cout <<count<< endl;
      20         if (n <= count)
      21             return true;
      22         else
      23             return false;
      24         }
      25     };
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  • 原文地址:https://www.cnblogs.com/wujufengyun/p/7197310.html
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