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  • java-正则表达式练习

    正则表达式练习

    判断身份证:要么是15位,要么是18位,最后一位可以为字母,并写程序提出其中的年月日。

    复制代码
    public static void main(String[] args) {
            testID_Card();
        }
    
        public static void testID_Card() {
            // 测试是否为合法的身份证号码
            String[] strs = { "130681198712092019", "13068119871209201x",
                    "13068119871209201", "123456789012345", "12345678901234x",
                    "1234567890123" };
            // 准备正则表达式(身份证有15位和18位两种,身份证的最后一位可能是字母)
            String regex = "(\d{14}\w)|\d{17}\w";
            // 准备开始匹配,判断所有的输入是否是正确的
            Pattern regular = Pattern.compile(regex); // 创建匹配的规则Patter
    
            StringBuilder sb = new StringBuilder();
            // 遍历所有要匹配的字符串
            for (int i = 0; i < strs.length; i++) {
    
                Matcher matcher = regular.matcher(strs[i]);// 创建一个Matcher
                sb.append("身份证:  ");
                sb.append(strs[i]);
                sb.append("   匹配:");
                sb.append(matcher.matches());
                System.out.println(sb.toString());
                sb.delete(0, sb.length());// 清空StringBuilder的方法
            }
    
            GetBirthDay(strs);
    
        }
    
        private static void GetBirthDay(String[] strs) {
            System.out.println("准备开始获取出生日期");
            // 准备验证规则
            Pattern BirthDayRegular = Pattern.compile("(\d{6})(\d{8})(.*)");
            // .*连在一起就意味着任意数量的不包含换行的字符
            Pattern YearMonthDayRegular = Pattern
                    .compile("(\d{4})(\d{2})(\d{2})");
            for (int i = 0; i < strs.length; i++) {
                Matcher matcher = BirthDayRegular.matcher(strs[i]);
    
                if (matcher.matches()) {
                    Matcher matcher2 = YearMonthDayRegular
                            .matcher(matcher.group(2));
                    if (matcher2.matches()) {
                        System.out.println(strs[i]+"    中的出生年月分解为: "+"年" + matcher2.group(1) + "   月:"
                                + matcher2.group(2) + "  日:" + matcher2.group(3));
    
                    }
                }
            }
    
        }
    复制代码
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  • 原文地址:https://www.cnblogs.com/wuqiance/p/11605027.html
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