zoukankan      html  css  js  c++  java
  • Maximum Clique

    Maximum Clique

    Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 92 Accepted Submission(s): 60
     
    Problem Description
    Given a graph G(V, E), a clique is a sub-graph g(v, e), so that for all vertex pairs v1, v2 in v, there exists an edge (v1, v2) in e. Maximum clique is the clique that has maximum number of vertex.
     
    Input
    Input contains multiple tests. For each test:

    The first line has one integer n, the number of vertex. (1 < n <= 50)

    The following n lines has n 0 or 1 each, indicating whether an edge exists between i (line number) and j (column number).

    A test with n = 0 signals the end of input. This test should not be processed.
     
    Output

                One number for each test, the number of vertex in maximum clique.
     
    Sample Input
    5
    0 1 1 0 1
    1 0 1 1 1
    1 1 0 1 1
    0 1 1 0 1
    1 1 1 1 0
    0
     
    Sample Output
    4
     
    Author
    CHENG, Long
     
    Source
    ZOJ Monthly, February 2003
     
    Recommend
    mcqsmall
     
    /*
    题意:就是给你一个图,然后输出最大团嘛
    */
    #include<bits/stdc++.h>
    using namespace std;
    
    /***********************************最大团模板************************************/
    struct MAX_CLIQUE {
        static const int N=60;
    
        bool G[N][N];
        int n, Max[N], Alt[N][N], ans;
    
        bool DFS(int cur, int tot) {
            if(cur==0) {
                if(tot>ans) {
                    ans=tot;
                    return 1;
                }
                return 0;
            }
            for(int i=0; i<cur; i++) {
                if(cur-i+tot<=ans) return 0;
                int u=Alt[tot][i];
                if(Max[u]+tot<=ans) return 0;
                int nxt=0;
                for(int j=i+1; j<cur; j++)
                    if(G[u][Alt[tot][j]]) Alt[tot+1][nxt++]=Alt[tot][j];
                if(DFS(nxt, tot+1)) return 1;
            }
            return 0;
        }
    
        int MaxClique() {
            ans=0, memset(Max, 0, sizeof Max);
            for(int i=n-1; i>=0; i--) {
                int cur=0;
                for(int j=i+1; j<n; j++) if(G[i][j]) Alt[1][cur++]=j;
                DFS(cur, 1);
                Max[i]=ans;
            }
            return ans;
        }
    };
    
    MAX_CLIQUE fuck;
    /***********************************最大团模板************************************/
    int n;
    int main(){
        // freopen("in.txt","r",stdin);
        while(scanf("%d",&fuck.n)!=EOF&&fuck.n){
            for(int i=0;i<fuck.n;i++){
                for(int j=0;j<fuck.n;j++){
                    scanf("%d",&fuck.G[i][j]);
                }
            }
            printf("%d
    ",fuck.MaxClique());
        }
        return 0;
    }
  • 相关阅读:
    JS语言中的JSON.parse()和JSON.stringify()
    Django中 @login_required用法简介
    Django model中的save后的return
    windows下gethostbyname 调用失败
    学习打造自己的DEBUG_NEW
    关于new/delete、malloc/free的内存泄漏检测
    C++连接mysql的两种方式(ADO连接和mysql api连接)
    windows下Redis编译安装
    mysql之字符编码问题
    mysql错误用法insert into where
  • 原文地址:https://www.cnblogs.com/wuwangchuxin0924/p/6414199.html
Copyright © 2011-2022 走看看