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  • LeetCode

    X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions.

    Please write a SQL query to output movies with an odd numbered ID and a description that is not 'boring'. Order the result by rating.

    For example, table cinema:

    +---------+-----------+--------------+-----------+
    |   id    | movie     |  description |  rating   |
    +---------+-----------+--------------+-----------+
    |   1     | War       |   great 3D   |   8.9     |
    |   2     | Science   |   fiction    |   8.5     |
    |   3     | irish     |   boring     |   6.2     |
    |   4     | Ice song  |   Fantacy    |   8.6     |
    |   5     | House card|   Interesting|   9.1     |
    +---------+-----------+--------------+-----------+
    

    For the example above, the output should be:

    +---------+-----------+--------------+-----------+
    |   id    | movie     |  description |  rating   |
    +---------+-----------+--------------+-----------+
    |   5     | House card|   Interesting|   9.1     |
    |   1     | War       |   great 3D   |   8.9     |
    +---------+-----------+--------------+-----------+

    # Write your MySQL query statement below
    select * from cinema where description != 'boring' and (id % 2) = 1 group by rating desc
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  • 原文地址:https://www.cnblogs.com/wxisme/p/7516721.html
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