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  • LeetCode

    The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id.

    +----+-------+--------+--------------+
    | Id | Name  | Salary | DepartmentId |
    +----+-------+--------+--------------+
    | 1  | Joe   | 70000  | 1            |
    | 2  | Henry | 80000  | 2            |
    | 3  | Sam   | 60000  | 2            |
    | 4  | Max   | 90000  | 1            |
    | 5  | Janet | 69000  | 1            |
    | 6  | Randy | 85000  | 1            |
    +----+-------+--------+--------------+
    

    The Department table holds all departments of the company.

    +----+----------+
    | Id | Name     |
    +----+----------+
    | 1  | IT       |
    | 2  | Sales    |
    +----+----------+
    

    Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows.

    +------------+----------+--------+
    | Department | Employee | Salary |
    +------------+----------+--------+
    | IT         | Max      | 90000  |
    | IT         | Randy    | 85000  |
    | IT         | Joe      | 70000  |
    | Sales      | Henry    | 80000  |
    | Sales      | Sam      | 60000  |
    +------------+----------+--------+

    # Write your MySQL query statement below
    SELECT
        d.`Name` AS Department,
        e1. NAME AS Employee,
        e1.Salary
    FROM
        employee e1 JOIN
        department d ON e1.DepartmentId=d.Id
    WHERE
        3 > (
            SELECT
                COUNT(DISTINCT Salary)
            FROM
                employee e2
            WHERE
                e2.Salary > e1.Salary
            AND e1.DepartmentId = e2.DepartmentId
        )
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  • 原文地址:https://www.cnblogs.com/wxisme/p/7544487.html
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