Trie 树的一个应用
Design a data structure that supports the following two operations:
void addWord(word) bool search(word)
search(word) can search a literal word or a regular expression string containing only letters a-z
or .
. A .
means it can represent any one letter.
For example:
addWord("bad") addWord("dad") addWord("mad") search("pad") -> false search("bad") -> true search(".ad") -> true search("b..") -> true
Note:
You may assume that all words are consist of lowercase letters a-z
.
class TrieNode{ public: TrieNode* child[26]; bool isWord = false; TrieNode() : isWord(false){ for(auto &a : child) a = nullptr; } }; class WordDictionary{ private: TrieNode* root = new TrieNode(); public: void addWord(string word){ TrieNode* p = root; for(auto &a : word){ int i = a - 'a'; if(p->child[i] == nullptr) p->child[i] = new TrieNode(); p = p->child[i]; } p->isWord = true; } bool search(string word){ int n = word.length(); return search(word,n,0,root); } bool search(string& word,int n,int pos,TrieNode* cur){ if(pos == n) return cur->isWord; if(cur == nullptr) return false; if(word[pos] == '.'){ for(int i=0;i<26;i++){ if(cur->child[i]){ if(search(word,n,pos+1,cur->child[i])){ return true; } } } }else{ int i = word[pos] - 'a'; if(cur->child[i]) return search(word,n,pos+1,cur->child[i]); } return false; } };