19、显示表达式的运算形式

显示表达式的运算形式

1、显示表达式1*2+3*4+...+9*10的运算表示形式 

源程序代码如下：

/*
    2017年6月7日22:54:51
    功能：实现1*2+3*4+...+9*10表达式的操作

*/
#include "stdio.h"
#include "string.h"

char a[100];
int i, j = 0;
int main()
{
    for(i = 1; i <= 10; i++)
    {
        if(i % 2 != 0)
        {
            a[j++] = i +'0';
            a[j++] = '*';
        }
        else if(i % 2 == 0 && i != 10)
        {
            a[j++] = i +'0';
            a[j++] = '+';
        }
        else 
        {
            a[j++] = 1 + '0';
            a[j++] = '0';
        }

    }
    a[j] = '';
    puts(a);
    return 0;
}
/*
    总结：
    在VC++6.0中显示的结果：
    ——————————————————
    1*2+3*4+5*6+7*8+9*10
    ——————————————————

*/

2、显示表达式1*2+3*4+...+99*100的运算表示形式　

 源程序代码如下：

/*
    2017年6月7日22:44:12
    功能：显示表达式1*2+3*4+...+99*100的表示形式
*/

#include"stdio.h"
#include"string.h"

int main()
{
    char seq[10000] = "alex";
    int i, j = 0, first, second;
    for (i = 1; i <= 100; i++)
    {
        if (i < 10)
            if (i % 2 != 0)
                seq[j++] = '0' + i,seq[j++] = '*';
            else
                seq[j++] = '0' + i,seq[j++] = '+';
        else if (i >= 10 && i <= 99)
        {
            first = i % 10;
            second = (i - first) / 10;
            if (i % 2 != 0)
                seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '*';
            else
                seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '+';
        }
        else if (i == 100)
            seq[j++] = '0' + 1,seq[j++] = '0',seq[j] = '0';
        
    }
    puts(seq);
    return 0;
}


/*
    总结：
    在VC++6.0中显示的结果:
    ——————————————————————————————————
    1*2+3*4+5*6+7*8+9*10+11*12+13*14+15*16+17*18+19*20+21*22+23*24+25*26
    +27*28+29*30+31*32+33*34+35*36+37*38+39*40+41*42+43*44+45*46+47*48+
    49*50+51*52+53*54+55*56+57*58+59*60+61*62+63*64+65*66+67*68+69*70+
    71*72+73*74+75*76+77*78+79*80+81*82+83*84+85*86+87*88+89*90+91*92+
    93*94+95*96+97*98+99*100


    ——————————————————————————————————
*/ 

3、显示表达式1*2+3*4+...+99*100的运算表示形式（采取交互的形式）

程序源代码如下：

/*
    2017年6月8日08:03:38
    功能：采取交互的形式输出以下的表达式
*/
#include "stdio.h"
#include "string.h"

int main()
{
    char seq[1000];
    int i, j = 0, first, second, num;
    printf("please input a odd number: ");
    scanf("%d",&num);
    if(num <= 10)
    {
        for (i = 1; i <= num; i++)
        {
             if (i % 2 != 0)
                seq[j++] = '0' + i,seq[j++] = '*';
             else if(i % 2 == 0 && i != num)
                seq[j++] = '0' + i,seq[j++] = '+';
             else if (i == num)     
                seq[j++] = '0' + 1,seq[j++] = '0';
        }
    }
    else if(num > 10 && num < 100)
    {
        for (i = 1; i <= num; i++)    
        {
            if (i < 10)
                 if (i % 2 != 0)
                     seq[j++] = '0' + i,seq[j++] = '*';
                 else
                     seq[j++] = '0' + i,seq[j++] = '+';
             else if (i >= 10 && i < num)
             {
                 first = i % 10;
                 second = (i - first) / 10;
                 if (i % 2 != 0)
                     seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '*';
                 else if (i % 2 == 0 && i != num)
                     seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '+';
             }
             else if (i == num)
                 seq[j++] = '0' + second ,seq[j++] = '0' + (first + 1) ;
        }

    }
    else if(num == 100)
    {
        for (i = 1; i <= 100; i++)    
        {
            if (i < 10)
                 if (i % 2 != 0)
                     seq[j++] = '0' + i,seq[j++] = '*';
                 else
                     seq[j++] = '0' + i,seq[j++] = '+';
             else if (i >= 10 && i < 100)
             {
                 first = i % 10;
                 second = (i - first) / 10;
                 if (i % 2 != 0)
                     seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '*';
                 else
                     seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '+';
             }
             else if (i == 100)
                 seq[j++] = '0' + 1,seq[j++] = '0',seq[j++] = '0';
        }
    }
    seq[j] = '';
    puts(seq);
}
/*
    总结：
    在VC++6.0中显示的结果：
    -----------------------------------------------------------------
    please input a odd number: 98
    1*2+3*4+5*6+7*8+9*10+11*12+13*14+15*16+17*18+19*20+21*22+23*24+25*26+27*28+29*30
    +31*32+33*34+35*36+37*38+39*40+41*42+43*44+45*46+47*48+49*50+51*52+53*54+55*56+5
    7*58+59*60+61*62+63*64+65*66+67*68+69*70+71*72+73*74+75*76+77*78+79*80+81*82+83*
    84+85*86+87*88+89*90+91*92+93*94+95*96+97*98

    please input a odd number: 100
    1*2+3*4+5*6+7*8+9*10+11*12+13*14+15*16+17*18+19*20+21*22+23*24+25*26+27*28+29*30
    +31*32+33*34+35*36+37*38+39*40+41*42+43*44+45*46+47*48+49*50+51*52+53*54+55*56+5
    7*58+59*60+61*62+63*64+65*66+67*68+69*70+71*72+73*74+75*76+77*78+79*80+81*82+83*
    84+85*86+87*88+89*90+91*92+93*94+95*96+97*98+99*100
    -----------------------------------------------------------------
    注意：将整数型数据转化成字符型数据的格式
            char m;
            int n;
            m = n + '0';（像10、100之类的数据除外）
*/