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  • 剑指offer19:按照从外向里以顺时针的顺序依次打印出每一个数字,4 X 4矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

    1 题目描述

      输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,例如,如果输入如下4 X 4矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

    2 思路和方法

      直接定义一个矩形,在矩形的四条边取值,程序大大简化。

    3 核心代码

     1 class Solution {
     2 public:
     3     vector<int> printMatrix(vector<vector<int> > matrix) {
     4         vector<int>vec;
     5         int row = matrix.size();
     6         int column = matrix[0].size();
     7         int left = 0, right = column, up = 0, bottom = row;
     8         while((up < bottom) && (left < right))
     9         {
    10             for(int i = left; i < right; i++) vec.push_back(matrix[up][i]);
    11             for(int i = up+1; i < bottom; i++) vec.push_back(matrix[i][right-1]);
    12             for(int i = right-1-1; ((bottom-1)!=up)&&(i >=left); i--) vec.push_back(matrix[bottom-1][i]);
    13             for(int i = bottom-1-1; ((right-1)!=left)&&(i >left); i--) vec.push_back(matrix[i][left]);
    14             up++;left++; right--; bottom--;
    15         }
    16         return vec;
    17     }
    18 };
    View Code

    4 完整代码

     1 #include<iostream>
     2 #include<vector>
     3 
     4 using namespace std;
     5 
     6 //直接定义一个矩形,在矩形的四条边取值,程序大大简化
     7 class Solution{
     8 public:
     9     vector<int>printMatrix(vector<vector<int>>  matrix) {
    10         vector<int>vec;
    11         int row = matrix.size();
    12         int column = matrix[0].size();
    13         int left = 0, right = column, up = 0, bottom = row;
    14         while ((up < bottom) && (left < right))
    15         {
    16             for (int i = left; i < right; i++) vec.push_back(matrix[up][i]);
    17             for (int i = up + 1; i < bottom; i++) vec.push_back(matrix[i][right - 1]);
    18             for (int i = right - 1 - 1; ((bottom - 1) != up) && (i >= left); i--) vec.push_back(matrix[bottom - 1][i]);
    19             for (int i = bottom - 1 - 1; ((right - 1) != left) && (i >left); i--) vec.push_back(matrix[i][left]);
    20             up++; left++; right--; bottom--;
    21         }
    22         return vec;
    23     }
    24 };
    25 
    26 int main()
    27 
    28 {
    29     Solution a;
    30     vector<vector<int>> matrix = { { 1, 2, 3, 4, 5 }, { 6, 7, 8, 9, 10 }, { 11, 12, 13, 14, 15 } };//矩阵初始化
    31     vector<int> m = a.printMatrix(matrix);
    32     for (auto i : m)//依次打印返回矩阵的值
    33         cout << i << " ";
    34     cout << endl;
    35 
    36     return 0;
    37 
    38 }
    View Code

    参考资料

    https://blog.csdn.net/hangsyt108/article/details/80949337

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  • 原文地址:https://www.cnblogs.com/wxwhnu/p/11410207.html
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