zoukankan      html  css  js  c++  java
  • Codeforces 832A. Sasha and Sticks

    It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.

    Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws n sticks in a row. After that the players take turns crossing out exactly k sticks from left or right in each turn. Sasha moves first, because he is the inventor of the game. If there are less than k sticks on the paper before some turn, the game ends. Sasha wins if he makes strictly more moves than Lena. Sasha wants to know the result of the game before playing, you are to help him.

    Input

    The first line contains two integers n and k (1 ≤ n, k ≤ 1018, k ≤ n) — the number of sticks drawn by Sasha and the number k — the number of sticks to be crossed out on each turn.

    Output

    If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).

    You can print each letter in arbitrary case (upper of lower).

    Examples
    input
    1 1
    output
    YES
    input
    10 4
    output
    NO
    Note

    In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.

    In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sasha doesn't win.

     1 #include <iostream>
     2 #include <stdio.h>
     3 #include <cstring>
     4 #include <algorithm>
     5 using namespace std;
     6 #define ll long long
     7 int main()
     8 {
     9     ll n,k;
    10     while(cin>>n>>k){
    11         ll a=n/k;
    12         if(a%2==0) cout<<"NO"<<endl;
    13         else cout<<"YES"<<endl;
    14     }
    15     return 0;
    16 }
  • 相关阅读:
    EBS OAF中如何在多行表中实现附件功能
    ubuntu12.04常见错误总结
    java InputStream使用
    免费送光盘了
    【原创】JAVA8之妙用Optional解决NPE问题
    【原创】分布式之redis复习精讲
    【原创】分布式之数据库和缓存双写一致性方案解析
    【原创】分布式之消息队列复习精讲
    【原创】分布式之延时任务方案解析
    【原创】自己动手循序渐进实现观察者模式
  • 原文地址:https://www.cnblogs.com/wydxry/p/7240547.html
Copyright © 2011-2022 走看看