zoukankan      html  css  js  c++  java
  • Codeforce 834A

    Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.

    Spinners in Sweetland have the form of V-shaped pieces of caramel. Each spinner can, well, spin around an invisible magic axis. At a specific point in time, a spinner can take 4 positions shown below (each one rotated 90 degrees relative to the previous, with the fourth one followed by the first one):

    After the spinner was spun, it starts its rotation, which is described by a following algorithm: the spinner maintains its position for a second then majestically switches to the next position in clockwise or counter-clockwise order, depending on the direction the spinner was spun in.

    Slastyona managed to have spinner rotating for exactly n seconds. Being fascinated by elegance of the process, she completely forgot the direction the spinner was spun in! Lucky for her, she managed to recall the starting position, and wants to deduct the direction given the information she knows. Help her do this.

    Input

    There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated by a single space.

    In the second strings, a single number n is given (0 ≤ n ≤ 109) – the duration of the rotation.

    It is guaranteed that the ending position of a spinner is a result of a n second spin in any of the directions, assuming the given starting position.

    Output

    Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise.

    Examples
    input
    ^ >
    1
    output
    cw
    input
    < ^
    3
    output
    ccw
    input
    ^ v
    6
    output
    undefined

    题解:分情况来嘛,偶次就不用管了只需要讨论奇次
     1 #include <iostream>
     2 #include <algorithm>
     3 #include <cstring>
     4 #include <cstdio>
     5 #include <vector>
     6 #include <cstdlib>
     7 #include <iomanip>
     8 #include <cmath>
     9 #include <ctime>
    10 #include <map>
    11 #include <set>
    12 using namespace std;
    13 #define lowbit(x) (x&(-x))
    14 #define max(x,y) (x>y?x:y)
    15 #define min(x,y) (x<y?x:y)
    16 #define MAX 100000000000000000
    17 #define MOD 1000000007
    18 #define pi acos(-1.0)
    19 #define ei exp(1)
    20 #define PI 3.141592653589793238462
    21 #define INF 0x3f3f3f3f3f
    22 #define mem(a) (memset(a,0,sizeof(a)))
    23 typedef long long ll;
    24 const int N=1005;
    25 const int mod=1e9+7;
    26 int main()
    27 {
    28     char a,b;
    29     int n;
    30     scanf("%c %c",&a,&b);
    31     scanf("%d",&n);
    32     if(n%2==0) printf("undefined
    ");
    33     else if(a=='^'&&b=='>'){
    34         if(n%4==1) printf("cw
    ");
    35         else if(n%4==3) printf("ccw
    ");
    36     }
    37     else if(a=='^'&&b=='<'){
    38         if(n%4==1) printf("ccw
    ");
    39         else if(n%4==3) printf("cw
    ");
    40     }
    41     else if(a=='>'&&b=='^'){
    42         if(n%4==1) printf("ccw
    ");
    43         else if(n%4==3) printf("cw
    ");
    44     }
    45     else if(a=='>'&&b=='v'){
    46         if(n%4==1) printf("cw
    ");
    47         else if(n%4==3) printf("ccw
    ");
    48     }
    49     else if(a=='v'&&b=='>'){
    50         if(n%4==1) printf("ccw
    ");
    51         else if(n%4==3) printf("cw
    ");
    52     }
    53     else if(a=='v'&&b=='<'){
    54         if(n%4==1) printf("cw
    ");
    55         else if(n%4==3) printf("ccw
    ");
    56     }
    57     else if(a=='<'&&b=='^'){
    58         if(n%4==1) printf("cw
    ");
    59         else if(n%4==3) printf("ccw
    ");
    60     }
    61     else if(a=='<'&&b=='v'){
    62         if(n%4==1) printf("ccw
    ");
    63         else if(n%4==3) printf("cw
    ");
    64     }
    65     return 0;
    66 }
     
  • 相关阅读:
    mybatis 入门基础
    spring学习总结
    综合练习:词频统计
    组合数据类型综合练习
    Python基础综合练习
    熟悉常用的Linux操作
    1.大数据概述
    C程序语法(无左递归)
    文法规则
    实验一词法分析报告
  • 原文地址:https://www.cnblogs.com/wydxry/p/7261817.html
Copyright © 2011-2022 走看看