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  • MySQL视图

    /*
    含义:虚拟表,和普通表一样使用
    mysql5.1版本出现的新特性,是通过表动态生成的数据
    比如:舞蹈班和普通班级的对比
    创建语法的关键字 是否实际占用物理空间 使用
    视图:create view 没有(只是保存了sql逻辑 增删改查) 只是一般不能增删改
    表: create table 占用 (保存了数据) 增删改查
    */

    #案例:查询姓张的学生名和专业名
    SELECT stuname,majorname
    FROM stuinfo s
    INNER JOIN major m ON s.`majorid`= m.`id`
    WHERE s.`stuname` LIKE '张%';
    
    CREATE VIEW v1
    AS
    SELECT stuname,majorname
    FROM stuinfo s
    INNER JOIN major m ON s.`majorid`= m.`id`;
    
    SELECT * FROM v1 WHERE stuname LIKE '张%';

    #一、创建视图
    /*
    语法:

    create view 视图名
    as
    查询语句;

      

    */
    USE myemployees;

    #1.查询姓名中包含a字符的员工名、部门名和工种信息
    #①创建
    CREATE VIEW myv1
    AS
    SELECT last_name,department_name,job_title
    FROM employees e
    JOIN departments d ON e.department_id = d.department_id
    JOIN jobs j ON j.job_id = e.job_id;
    
    
    #②使用
    SELECT * FROM myv1 WHERE last_name LIKE '%a%';
    
    
    #2.查询各部门的平均工资级别
    #①创建视图查看每个部门的平均工资
    CREATE VIEW myv2
    AS
    SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id;
    
    
    #②使用
    SELECT myv2.`ag`,g.grade_level
    FROM myv2
    JOIN job_grades g
    ON myv2.`ag` BETWEEN g.`lowest_sal` AND g.`highest_sal`;
    
    
    #3.查询平均工资最低的部门信息
    SELECT * FROM myv2 ORDER BY ag LIMIT 1;
    
    
    #4.查询平均工资最低的部门名和工资
    CREATE VIEW myv3
    AS
    SELECT * FROM myv2 ORDER BY ag LIMIT 1;
    
    
    SELECT d.*,m.ag
    FROM myv3 m
    JOIN departments d
    ON m.`department_id`=d.`department_id`;

    #二、视图的修改
    #方式一:
    /*

    create or replace view 视图名
    as
    查询语句;

    */

    SELECT * FROM myv3
    CREATE OR REPLACE VIEW myv3
    AS
    SELECT AVG(salary),job_id
    FROM employees
    GROUP BY job_id;

    #方式二:
    /*
    语法:

    alter view 视图名
    as
    查询语句;

    */

    ALTER VIEW myv3
    AS
    SELECT * FROM employees;


    #三、删除视图
    /*
    语法:

    drop view 视图名,视图名,...;

    */

    DROP VIEW emp_v1,emp_v2,myv3;


    #四、查看视图

    DESC myv3;
    
    
    SHOW CREATE VIEW myv3;

    #五、视图的更新

    CREATE OR REPLACE VIEW myv1
    AS
    SELECT last_name,email,salary*12*(1+IFNULL(commission_pct,0)) "annual salary"
    FROM employees;
    
    
    CREATE OR REPLACE VIEW myv1
    AS
    SELECT last_name,email
    FROM employees;
    
    
    SELECT * FROM myv1;
    
    
    SELECT * FROM employees;
    
    #1.插入
    INSERT INTO myv1 VALUES('张飞','zf@qq.com');
    
    #2.修改
    UPDATE myv1 SET last_name = '张无忌' WHERE last_name='张飞';
    
    #3.删除
    DELETE FROM myv1 WHERE last_name = '张无忌';
    
    #具备以下特点的视图不允许更新
    
    #①包含以下关键字的sql语句:分组函数、distinctgroup byhaving、union或者union all
    CREATE OR REPLACE VIEW myv1
    AS
    SELECT MAX(salary) m,department_id
    FROM employees
    GROUP BY department_id;
    
    
    SELECT * FROM myv1;
    
    #更新
    UPDATE myv1 SET m=9000 WHERE department_id=10;
    
    #②常量视图
    CREATE OR REPLACE VIEW myv2
    AS
    SELECT 'john' NAME;
    
    
    SELECT * FROM myv2;
    
    #更新
    UPDATE myv2 SET NAME='lucy';
    
    
    
    #③Select中包含子查询
    CREATE OR REPLACE VIEW myv3
    AS
    SELECT department_id,(SELECT MAX(salary) FROM employees) 最高工资
    FROM departments;
    
    #更新
    SELECT * FROM myv3;
    
    
    UPDATE myv3 SET 最高工资=100000;
    
    
    #④join
    CREATE OR REPLACE VIEW myv4
    AS
    SELECT last_name,department_name
    FROM employees e
    JOIN departments d
    ON e.department_id = d.department_id;
    
    #更新
    SELECT * FROM myv4;
    
    
    UPDATE myv4 SET last_name = '张飞' WHERE last_name='Whalen';
    INSERT INTO myv4 VALUES('陈真','xxxx');
    
    
    #⑤from一个不能更新的视图
    CREATE OR REPLACE VIEW myv5
    AS
    SELECT * FROM myv3;
    
    #更新
    SELECT * FROM myv5;
    
    
    UPDATE myv5 SET 最高工资=10000 WHERE department_id=60;
    
    
    #⑥where子句的子查询引用了from子句中的表
    CREATE OR REPLACE VIEW myv6
    AS
    SELECT last_name,email,salary
    FROM employees
    WHERE employee_id IN(
    SELECT manager_id
    FROM employees
    WHERE manager_id IS NOT NULL
    );
    
    #更新
    SELECT * FROM myv6;
    
    
    UPDATE myv6 SET salary=10000 WHERE last_name = 'k_ing';
    
     
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  • 原文地址:https://www.cnblogs.com/wzhqzm/p/13387672.html
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