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  • 687. Longest Univalue Path

    Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root.

    Note: The length of path between two nodes is represented by the number of edges between them.

    Example 1:

    Input:

                  5
                 / 
                4   5
               /    
              1   1   5
    

    Output:

    2

    Example 2:

    Input:

                  1
                 / 
                4   5
               /    
              4   4   5
    

    Output:

    2

    Note: The given binary tree has not more than 10000 nodes. The height of the tree is not more than 1000.

    题目含义:找出二叉树中,最长的链路长度(由相同值构成的链路,可以不包含根节点)

     1     private int sameNodeValue(TreeNode node, int[] res) {
     2         int l = node.left != null ? sameNodeValue(node.left, res) : 0;
     3         int r = node.right != null ? sameNodeValue(node.right, res) : 0;
     4         int resl = node.left != null && node.left.val == node.val ? l + 1 : 0;
     5         int resr = node.right != null && node.right.val == node.val ? r + 1 : 0;
     6         res[0] = Math.max(res[0], resl + resr);
     7         return Math.max(resl, resr);
     8     }    
     9     
    10     public int longestUnivaluePath(TreeNode root) {
    11         int[] res = new int[1];
    12         if (root != null) sameNodeValue(root, res);
    13         return res[0];        
    14     }
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  • 原文地址:https://www.cnblogs.com/wzj4858/p/7710831.html
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