zoukankan      html  css  js  c++  java
  • 230. Kth Smallest Element in a BST

    Given a binary search tree, write a function kthSmallest to find the kth smallest element in it.

    Note: 
    You may assume k is always valid, 1 ≤ k ≤ BST's total elements.

    Follow up:
    What if the BST is modified (insert/delete operations) often and you need to find the kth smallest frequently? How would you optimize the kthSmallest routine?

    题目含义:给出二叉搜索树中第k小的数字

     1     private int leftTreeNodeCount(TreeNode root) {
     2         if (root == null) return 0;
     3         return 1 + leftTreeNodeCount(root.left) + leftTreeNodeCount(root.right);
     4     }
     5     
     6     public int kthSmallest(TreeNode root, int k) {
     7 //        在二叉搜索树种,找到第K个小的元素。
     8 //        算法如下:
     9 //        1、计算左子树元素个数left。
    10 //        2、 left+1 = K,则根节点即为第K个元素
    11 //        3、left >=k, 则第K个元素在左子树中,
    12 //        4、left +1 <k, 则转换为在右子树中,寻找第K-left-1元素
    13         int leftCount = leftTreeNodeCount(root.left);
    14         if (leftCount >= k) {
    15             return kthSmallest(root.left, k);
    16         } 
    17         if (leftCount + 1 < k) return kthSmallest(root.right, k - leftCount - 1);
    18         return root.val;        
    19     }
  • 相关阅读:
    [状压DP]JZOJ 3293 阶乘字符串
    [线段树][Splay][树状数组]JZOJ 3292 发牌
    MySQL之索引
    MySQL(二)
    mysql 练习题
    前端 jQuery
    关于vertical-align和line-height的真知灼见
    CSS语法
    HTML初识
    HTTP协议
  • 原文地址:https://www.cnblogs.com/wzj4858/p/7712175.html
Copyright © 2011-2022 走看看