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  • leetcode

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.

    For example:
    Given the below binary tree and sum = 22,
                  5
                 / 
                4   8
               /   / 
              11  13  4
             /      / 
            7    2  5   1
    

    return

    [
       [5,4,11,2],
       [5,8,4,5]
    ]

    /**
     * Definition for binary tree
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    struct TreeNode
    {
    	int val;
    	TreeNode *left;
    	TreeNode *right;
    	TreeNode(int x) : val(x), left(NULL), right(NULL) {}
    };
    class Solution {
    public:
    	std::vector<std::vector<int> > pathSum(TreeNode *root, int sum) {
            dfs(root,sum,0,std::vector<int>(0));
    		return res;
        }
    private:
    	std::vector<std::vector<int>> res;
    	void dfs(TreeNode *root, int sum, int n,std::vector<int> vec)
    	{
    		if(root == NULL) return;
    		if(root->left == NULL && root->right == NULL)
    		{
    			if(sum == root->val + n)
    			{
    				vec.push_back(root->val);
    				res.push_back(vec);
    			}
    		}
    		else
    		{
    			vec.push_back(root->val);
    			dfs(root->left,sum,n+root->val,vec);
    			dfs(root->right,sum,n+root->val,vec);
    		}
    	}
    };


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  • 原文地址:https://www.cnblogs.com/wzzkaifa/p/6746795.html
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