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  • [leetcode]Construct Binary Tree from Inorder and Postorder Traversal

    和上一题同理,不过root在postorder的最后

    /**
     * Definition for binary tree
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        template<typename Iter>
        TreeNode* make(Iter iFirst , Iter iLast , Iter pFirst , Iter pLast) {
            if(iFirst == iLast) return nullptr;
            if(pFirst == pLast) return nullptr;
            
            pLast--;
            Iter iRoot = find(iFirst , iLast , *pLast);
            TreeNode* root = new TreeNode(*iRoot);
            int leftSize = iRoot - iFirst;
            root -> left = make(iFirst , iRoot , pFirst , pFirst + leftSize);
            root -> right = make(iRoot+1 , iLast , pFirst + leftSize , pLast);
            return root;
        }
        TreeNode *buildTree(vector<int> &inorder, vector<int> &postorder) {
            if(inorder.size() == 0) return nullptr;
            return make(inorder.begin() , inorder.end() , postorder.begin() , postorder.end());
        }
    };
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  • 原文地址:https://www.cnblogs.com/x1957/p/3519549.html
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