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  • java中对list集合中的数据按照某一个属性进行分组

    import java.util.ArrayList;
    import java.util.HashMap;
    import java.util.HashSet;
    import java.util.Iterator;
    import java.util.List;
    import java.util.Map;
    import java.util.Set;
     
     
    public class ListSort {  
     
        /**
         * 按照List<Map<String,Object>>里面map的某个value重新封装成多个不同的list, 原始数据类型List<Map
         * <String,Object>>, 转换后数据类型Map<String,List<Map<String,Object>>>
         * 
         * @param list
         * @param oneMapKey
         * @return
         */
        private static Map<String, Object> change(List<Map<String, Object>> list, String oneMapKey) {
            Map<String, Object> resultMap = new HashMap<String, Object>();
            Set<Object> setTmp = new HashSet<Object>();
            for (Map<String, Object> tmp : list) {
                setTmp.add(tmp.get(oneMapKey));
            }
            Iterator<Object> it = setTmp.iterator();
            while (it.hasNext()) {
                String oneSetTmpStr = (String) it.next();
                List<Map<String, Object>> oneSetTmpList = new ArrayList<Map<String, Object>>();
                for (Map<String, Object> tmp : list) {
                    String oneMapValueStr = (String) tmp.get(oneMapKey);
                    if (oneMapValueStr.equals(oneSetTmpStr)) {
                        oneSetTmpList.add(tmp);
                    }
                }
                resultMap.put(oneSetTmpStr, oneSetTmpList);
            }
            return resultMap;
        }
     
        /**
         * 按照List<Map<String,Object>>里面map的某个value重新封装成多个不同的list, 原始数据类型List<Map
         * <String,Object>>, 转换后数据类型Map<String,List<Map<String,Object>>>
         * 
         * @param list
         * @param oneMapKey
         * @return
         */
        private static List<Map<String, Object>> change2(List<Map<String, Object>> inList, String oneMapKey,
                List<Map<String, Object>> outList) {
            // 1.将某个key的值存在set中
            Set<Object> setTmp = new HashSet<Object>();
            for (Map<String, Object> tmp : inList) {
                setTmp.add(tmp.get(oneMapKey));
            }
            // 2.遍历set
            Iterator<Object> it = setTmp.iterator();
            while (it.hasNext()) {
                String oneMapValueStr = "";
                String oneSetTmpStr = (String) it.next();
                Map<String, Object> oneSetTmpMap = new HashMap<String, Object>();
                List<Map<String, Object>> oneSetTmpList = new ArrayList<Map<String, Object>>();
     
                for (Map<String, Object> tmp : inList) {
                    oneMapValueStr = (String) tmp.get(oneMapKey);
                    if (oneSetTmpStr.equals(oneMapValueStr)) {
                        oneSetTmpMap.put("text", oneSetTmpStr);
                        oneSetTmpList.add(tmp);
                    }
                }
                oneSetTmpMap.put("array", oneSetTmpList);
                outList.add(oneSetTmpMap);
            }
            return outList;
        }
     
     public static void main(String[] args) {
            Map<String, Object> map1 = new HashMap<String, Object>();
            Map<String, Object> map2 = new HashMap<String, Object>();
            Map<String, Object> map3 = new HashMap<String, Object>();
            Map<String, Object> map4 = new HashMap<String, Object>();
     
            List<Map<String, Object>> inList = new ArrayList<Map<String, Object>>();
            map1.put("id", "111");
            map1.put("name", "tom");
            map1.put("sex", "male");
     
            map2.put("id", "222");
            map2.put("name", "jack");
            map2.put("sex", "male");
     
            map3.put("id", "333");
            map3.put("name", "lucy");
            map3.put("sex", "female");
     
            map4.put("id", "444");
            map4.put("name", "lucy");
            map4.put("sex", "female");
     
            inList.add(map1);
            inList.add(map2);
            inList.add(map3);
            inList.add(map4);
            System.out.println("原始inList:" + inList);
     
            Map<String, Object> resultMap = new HashMap<String, Object>();
            // resultMap = change(list, "sex");
            resultMap = change(inList, "name");
            System.out.println("按照map中的某个值重新封装后的resultMap:" + resultMap);
     
            List<Map<String, Object>> outList = new ArrayList<Map<String, Object>>();
            System.out.println("retList==1==:" + outList);
            outList = change2(inList, "name", outList);
            System.out.println("retList==2==:" + outList);
     
        }
    }
    


    //根据设备名称进行分组 Map<String, List<ModuleStatisticDetail>> collect = moduleStatisticDetails.stream() .collect(Collectors.groupingBy(ModuleStatisticDetail::getDeviceTypeName)); 复制代码 /** * 使用jdk1.8 lamada表达式排序 倒序排列 */ list=list.stream().sorted(Comparator.comparing(SortBean::getT1).reversed()).collect(Collectors.toList()); for (SortBean sortBean : list) { System.out.println(sortBean); } 复制代码
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  • 原文地址:https://www.cnblogs.com/xianz666/p/13602953.html
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