取一个任意数所有 和的等式

前几天，同学给出了一个算法题

 随便输入一个数，输出 相加等于这个数的所有等式，而且加数不能重复

  例如：6

  6=1+5；

  6=2+4;

  6=1+2+3;

  --------------------------------

  程序如下：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace _111301
{
    class Program
    {
        static int total = 0;
        static void Main(string[] args)
        {
            Console.WriteLine("请输入数字：");
            int Num = 0;
            Num =Convert.ToInt32(Console.ReadLine().ToString());
            Console.WriteLine("-----------------等式如下：-------------------");
            for (int i = 1; i < (Num % 2 == 0 ? Num / 2 : Num / 2 + 1);i++ )
            {
                PrintNum(Num.ToString() + "=" + i.ToString(), i, i, Num);
            }
            Console.WriteLine("------------共计："+total.ToString()+"个-------------------------");
            Console.ReadKey();
        }
        /// <summary>
        /// 打印数字
        /// </summary>
        /// <param name="preInfo">此数字前面数字</param>
        ///  /// <param name="preInfo">此前数字和</param>
        /// <param name="flagNum">当前标志数字</param>
        /// <param name="maxNum">输入数字</param>
        private static void PrintNum(string preInfo,int preTotal,int flagNum,int maxNum)
        {
            Console.WriteLine(preInfo + "+" + (maxNum - preTotal).ToString());
            total++;
            for (int i = flagNum + 1; i <= (maxNum - preTotal - 1) / 2; i++)
            {
                string tempPreInfo = preInfo;
                int tempPreTotal = preTotal;
                tempPreTotal += i;
                tempPreInfo += "+" + i.ToString();
                if (i<=maxNum-preTotal-1)
                {
                    PrintNum(tempPreInfo, tempPreTotal, i, maxNum);
                }else{
                    continue;
                }
            }

        }
    }
}

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